http://acm.hdu.edu.cn/showproblem.php?pid=4325 题意:给出n个区间和m个询问,每个询问为一个x,问有多少个区间包含了x. 思路: 因为数据量比较多,所以需要离散化.区间的离散化需要注意一下,如果端点不连续的话,需要额外插点. 区间情况就用树状数组来维护. #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using…

http://acm.hdu.edu.cn/showproblem.php?pid=4325 Flowers Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2577    Accepted Submission(s): 1263 Problem Description As is known to all, the blooming t…

http://acm.hdu.edu.cn/showproblem.php?pid=4325 Flowers Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2633    Accepted Submission(s): 1290 Problem Description As is known to all, the blooming t…

Flowers Problem Description As is known to all, the blooming time and duration varies between different kinds of flowers. Now there is a garden planted full of flowers. The gardener wants to know how many flowers will bloom in the garden in a specifi…

思路:这题的思路很容易想到,把所有时间点离散化,然后按时间一步一步来,当到达时间i的时候处理所有在i处的查询. 这个代码怎一个挫字了得 #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<vector> #define Maxn 100010 #define lowbit(x) (x&(-x)) using namespace…

Flowers Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 3150    Accepted Submission(s): 1549 Problem Description As is known to all, the blooming time and duration varies between different kinds…

#include<stdio.h>//数据弱线段树延迟更新水过 #define N 100100 struct node { int x,y,yanchi,num; }a[N*4]; void build(int t,int x,int y) { a[t].x=x; a[t].y=y; a[t].yanchi=0; a[t].num=0; if(x==y) return ; int temp=t<<1; int mid=(x+y)/2; build(temp,x,mid); bui…

很明显的区间加减单点查询.但由于规模大,于是离散化.在离散化的时候,可以把要查询的点也加入离散化的数组中. #include <iostream> #include <algorithm> #include <cstdio> #include <cstring> #define lowbit(x) ((x)&(-x)) #define LL __int64 using namespace std; int tpoint[400010]; int sa…

题意:给出一些花的开放时间段,然后询问某个时间点有几朵花正在开放. 由于ti<1e9,我们需要先将时间离散化,然后将时间点抽象为一个数组中的点,显然,我们需要进行区间更新和单点查询,可以考虑线段树与树状数组两种做法,一般的,树状数组是用来维护区间和与单点修改的,那么,如何通过树状数组进行区间更新和单点查询呢,联想到差分数组,差分数组可以在o(1)的时间内进行区间的更新,但是单点查询的效率为o(n),显然不能用于处理此题,这时,考虑树状数组维护差分数组,就可以o(logn)地进行区间更新(更新差分…

Flowers Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 4325 Description As is known to all, the blooming time and duration varies between different kinds of flowers. Now there is a garden plant…