题目链接: B. Coat of Anticubism time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output   As some of you know, cubism is a trend in art, where the problem of constructing volumetrical shape on a plane…
B. The Time 题目连接: http://www.codeforces.com/contest/622/problem/B Description You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes. Note that you should find only the time after a minutes, see the examples t…
A. Infinite Sequence 题目连接: http://www.codeforces.com/contest/622/problem/A Description Consider the infinite sequence of integers: 1, 1, 2, 1, 2, 3, 1, 2, 3, 4, 1, 2, 3, 4, 5.... The sequence is built in the following way: at first the number 1 is wr…
A. Divisibility Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/597/problem/A Description Find the number of k-divisible numbers on the segment [a, b]. In other words you need to find the number of such integer values x tha…
A. Towers 题目连接: http://www.codeforces.com/contest/37/problem/A Description Little Vasya has received a young builder's kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other…
题目链接: A. Vanya and Fence time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Vanya and his friends are walking along the fence of height h and they do not want the guard to notice them. In orde…
题意:给定 n 条边,判断是不是树. 析:水题,判断是不是树,首先是有没有环,这个可以用并查集来判断,然后就是边数等于顶点数减1. 代码如下: #include <bits/stdc++.h> using namespace std; const int maxn =1000 + 5; int p[maxn]; int Find(int x){ return x == p[x] ? x : p[x] = Find(p[x]); } int main(){ int n, m, x, y; cin…
https://codeforc.es/contest/1194/problem/B 好像也没什么思维,就是一个水题,不过蛮有趣的.意思是找缺黑色最少的行列十字.用O(n)的空间预处理掉一维,然后用O(n)的时间根据另一维计算出答案. #include<bits/stdc++.h> using namespace std; typedef long long ll; int n, m; string g[50005]; int rq[50005]; int main() { #ifdef Yi…
Codeforces 1082B Vova and Trophies https://vjudge.net/problem/CodeForces-1082B 题目: Vova has won nn trophies in different competitions. Each trophy is either golden or silver. The trophies are arranged in a row. The beauty of the arrangement is the le…
题意:给定初始数量的冰激凌,然后n个操作,如果是“+”,那么数量就会增加,如果是“-”,如果现有的数量大于等于要减的数量,那么就减掉,如果小于, 那么孩子就会离家.问你最后剩下多少冰激凌,和出走的孩子数量. 析:多水的一个题,就是一个模拟,如果是+,就加上,如果是‘-’,就判断一下,如果不够,就记录下来. 代码如下: #include <iostream> #include <cmath> #include <cstdlib> #include <set>…