给定两个字符串,你需要从这两个字符串中找出最长的特殊序列.最长特殊序列定义如下:该序列为某字符串独有的最长子序列(即不能是其他字符串的子序列).子序列可以通过删去字符串中的某些字符实现,但不能改变剩余字符的相对顺序.空序列为所有字符串的子序列,任何字符串为其自身的子序列.输入为两个字符串,输出最长特殊序列的长度.如果不存在,则返回 -1.示例 :输入: "aba", "cdc"输出: 3解析: 最长特殊序列可为 "aba" (或 "cd…

[LeetCode]522. Longest Uncommon Subsequence II 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/longest-uncommon-subsequence-ii/description/ 题目描述: Given a list of strings, you…

Given a list of strings, you need to find the longest uncommon subsequence among them. The longest uncommon subsequence is defined as the longest subsequence of one of these strings and this subsequence should not be any subsequence of the other stri…

Given a group of two strings, you need to find the longest uncommon subsequence of this group of two strings. The longest uncommon subsequence is defined as the longest subsequence of one of these strings and this subsequence should not be any subseq…

题目如下: 解题思路:因为given list长度最多是50,我的解法就比较随意了,直接用一个嵌套的循环,判断数组中每个元素是否是其他的subsequence,最后找出不属于任何元素subsequence的最长元素即可. 代码如下: class Solution(object): def isSubsequence(self, a, b): """ :type a: str :type b: str :rtype: int """ s = b f…

Given an unsorted array of integers, find the length of longest increasing subsequence. For example,Given [10, 9, 2, 5, 3, 7, 101, 18],The longest increasing subsequence is [2, 3, 7, 101], therefore the length is 4. Note that there may be more than o…

详见:https://leetcode.com/problems/longest-uncommon-subsequence-ii/description/ C++: 方法一: class Solution { public: int findLUSlength(vector<string>& strs) { int res = -1, j = 0, n = strs.size(); for (int i = 0; i < n; ++i) { for (j = 0; j <…

［抄题］: [暴力解法]: 时间分析: 空间分析: [优化后]: 时间分析: 空间分析: ［奇葩输出条件］: ［奇葩corner case］: ［思维问题］: ［一句话思路］: 两个单词的话,就是看谁长 ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: ［二刷］: ［三刷］: ［四刷］: ［五刷］: [五分钟肉眼debug的结果]: ［总结］: ［复杂度］:Time complexity: O() Space complex…

problem 521. Longest Uncommon Subsequence I 最长非共同子序列之一 题意: 两个字符串的情况很少,如果两个字符串相等,那么一定没有非共同子序列,反之,如果两个字符串不等,那么较长的那个字符串就是最长非共同子序列. solution: class Solution { public: int findLUSlength(string a, string b) { ; return max(a.size(), b.size()); } }; or class…

Given a list of strings, you need to find the longest uncommon subsequence among them. The longest uncommon subsequence is defined as the longest subsequence of one of these strings and this subsequence should not be any subsequence of the other stri…