LeetCode15——3Sum】的更多相关文章

题意: Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero. Note: The solution set must not contain duplicate triplets.  (Medium) For example, given a…
Given an array nums of n integers, are there elements a, b, c in nums such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero. Note: The solution set must not contain duplicate triplets. Example: Given array nums =…
数组中找三个数和为0的结果集 1 // 解法一:先排序 然后固定一个值 然后用求两个数的和的方式 public static List<List<Integer>> threeSum(int[] nums) { List<List<Integer>> res = new ArrayList<>(); if (nums.length < 3) { return res; } Arrays.sort(nums); // 遍历到倒数第三个就可以了…
给定一个包含 n 个整数的数组 nums,判断 nums 中是否存在三个元素 a,b,c ,使得 a + b + c = 0 ?找出所有满足条件且不重复的三元组. 注意:答案中不可以包含重复的三元组. 例如, 给定数组 nums = [-1, 0, 1, 2, -1, -4], 满足要求的三元组集合为: [ [-1, 0, 1], [-1, -1, 2] ] 双指针加去重 class Solution { public: vector<vector<int> > threeSum(…
15. 三数之和 15. 3Sum 题目描述 Given an array nums of n integers, are there elements a, b, c in nums such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero. Note: The solution set must not contain duplicate triplets. LeetC…
第六周.后期补完,太忙了. 1.Algorithm:每周至少做一个 leetcode 的算法题2.Review:阅读并点评至少一篇英文技术文章3.Tip:学习至少一个技术技巧4.Share:分享一篇有观点和思考的技术文章 以下是各项的情况: Algorithm 链接:[LeetCode-15]-3sum class Solution { public List<List<Integer>> threeSum(int[] nums) { List<List<Integer…
Given an array nums of n integers, are there elements a, b, c in nums such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero. Note: The solution set must not contain duplicate triplets. Example: Given array nums =…
Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero. Note: The solution set must not contain duplicate triplets. For example, given array S = [-1,…
原题重述:(点击图片可以进入来源链接) 这到题目的中文解释是, 输入一个数组,例如{-1 0 1 2 -1 -4},从数组中找三个数(a,b,c),使得其和0,输出所有的(a,b,c)组合. 要求abc不能重复,并且a<=b<=c. 拿到这个题目的时候,其实每个程序猿都能想到如下的算法,也就是暴力破解,其时间复杂度为o(n^3): for(int i=0;i<nums.length;i++){ for(int j=i+1;j<nums.length;j++){ for(int k=…
Given an array of n integers nums and a target, find the number of index triplets i, j, k with 0 <= i < j < k < n that satisfy the condition nums[i] + nums[j] + nums[k] < target. For example, given nums = [-2, 0, 1, 3], and target = 2. Retu…