https://leetcode.com/problems/count-numbers-with-unique-digits/ 给定一个n,计算[0,10^n]中十进制中每一位都不相同的数的数目. class Solution{ public: int countNumbersWithUniqueDigits(int n){ ; , n); ; i--){ ; ; j>; j--) tmp *= -i+j+; res+=tmp; } ; } };…

Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10n. Example: Input: 2 Output: 91 Explanation: The answer should be the total numbers in the range of 0 ≤ x < 100,   excluding 11,22,33,44,55,66,77,88,99 Runtime:…

Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10n. Example: Given n = 2, return 91. (The answer should be the total numbers in the range of 0 ≤ x < 100, excluding [11,22,33,44,55,66,77,88,99]) Hint: A direct…

Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10n. Example:Given n = 2, return 91. (The answer should be the total numbers in the range of 0 ≤ x < 100, excluding [11,22,33,44,55,66,77,88,99]) public class Sol…

Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10n. Example: Given n = 2, return 91. (The answer should be the total numbers in the range of 0 ≤ x < 100, excluding [11,22,33,44,55,66,77,88,99]) Analysis: A num…

Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10n. Example:Given n = 2, return 91. (The answer should be the total numbers in the range of 0 ≤ x < 100, excluding [11,22,33,44,55,66,77,88,99]) 代码如下: public cla…

题目描述: Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10n. 解题分析: 题目要就就是找出 0≤ x < 10n中各位数字都不相同的数的个数.要接触这道题只需要理解: 1.设f(n)表示n为数字中各位都不相同的个数,则有countNumbersWithUniqueDigits(n)=f(1)+f(2)+……+f(n)=f(n)+countNumbersWithU…

Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10n. Example: Input: 2 Output: 91 Explanation: The answer should be the total numbers in the range of 0 ≤ x < 100,   excluding 11,22,33,44,55,66,77,88,99 给定一个非负整数…

题目描述: Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10n. Example:Given n = 2, return 91. (The answer should be the total numbers in the range of 0 ≤ x < 100, excluding [11,22,33,44,55,66,77,88,99]) 解题思路: This…

Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10^n. Example:Given n = 2, return 91. (The answer should be the total numbers in the range of 0 ≤ x < 100, excluding [11,22,33,44,55,66,77,88,99]) 思路:DP dp[i]表示10…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/count-numbers-with-unique-digits/description/ 题目描述 Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x <…

给定一个非负整数 n,计算各位数字都不同的数字 x 的个数,其中 0 ≤ x < 10n.示例:给定 n = 2,返回 91.(答案应该是除[11,22,33,44,55,66,77,88,99]外,0 ≤ x < 100 间的所有数字) 详见:https://leetcode.com/problems/count-numbers-with-unique-digits/description/ C++: class Solution { public: int countNumbersWith…

Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10n. Example:Given n = 2, return 91. (The answer should be the total numbers in the range of 0 ≤ x < 100, excluding [11,22,33,44,55,66,77,88,99]) 思路: 思路: 排列组合题. 设…

https://leetcode.com/problems/numbers-with-repeated-digits/ 与leetcode_357. Count Numbers with Unique Digits有一些相似的地方. 给定N,计算小于等于N且至少有一个重复数位的数的数目. 可转化为计算小于等于N且所有数位不相同的数的数目.且可分为两部分, 位数与N相同且小于等于N且所有数位不相同的数的数目: 位数小于N且所有数位不相同的数的数目. 难点在于第1部分. 解法一: 使用dfs计算第一…

Count Numbers 时间限制: 8 Sec  内存限制: 128 MB提交: 43  解决: 19[提交] [状态] [讨论版] [命题人:admin] 题目描述 Now Alice wants to sum up all integers whose digit sum is exactly ab .However we all know the number of this kind of integers are unlimited. So she decides to sum u…

Count Numbers 时间限制: 8 Sec  内存限制: 128 MB 题目描述 Now Alice wants to sum up all integers whose digit sum is exactly ab .However we all know the number of this kind of integers are unlimited. So she decides to sum up all these numbers whose each digit is n…

题目如下: Given a positive integer N, return the number of positive integers less than or equal to N that have at least 1 repeated digit. Example 1: Input: 20 Output: 1 Explanation: The only positive number (<= 20) with at least 1 repeated digit is 11. E…

Given a positive integer N, return the number of positive integers less than or equal to N that have at least 1 repeated digit. Example 1: Input: 20 Output: 1 Explanation: The only positive number (<= 20) with at least 1 repeated digit is 11. Example…

2020-01-03 12:01:46 问题描述: 问题求解: 确实可以当作数学题去做,但是要分类讨论什么的还是有点麻烦的. 这个时候万能的dfs上场了,直接暴力检索,真的太强了. int res = 0; public int numDupDigitsAtMostN(int N) { dfs(0, 0, N); return N - res + 1; } private void dfs(long curr, int used, int N) { if (curr > N) return; r…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…

Problem Reason Reference Moving ZeroesSort Colors Corner cases   Shortest Word Distance Thought: 2 ptr chasing   Merge 2 sorted ListsRemove Linked List Elem Corner cases   Power of Four Thought: fun bit ops   Pow(x, n) int overflow   Rectangle Area T…

刷题备忘录,for bug-free leetcode 396. Rotate Function 题意: Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positions clock-wise, we define a "rotation function" F on A as follow: F(k…

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

2. Add Two Numbers https://leetcode.com/problems/add-two-numbers/description/ class Solution { public: ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { ListNode result(-); ListNode* current = &result; ; while(l1!=NULL || l2!=NULL){ ; ; if(l1!=NU…

刷题备忘录,for bug-free 招行面试题--求无序数组最长连续序列的长度,这里连续指的是值连续--间隔为1,并不是数值的位置连续 问题: 给出一个未排序的整数数组,找出最长的连续元素序列的长度. 如: 给出[100, 4, 200, 1, 3, 2], 最长的连续元素序列是[1, 2, 3, 4].返回它的长度:4. 你的算法必须有O(n)的时间复杂度 . 解法: 初始思路 要找连续的元素,第一反应一般是先把数组排序.但悲剧的是题目中明确要求了O(n)的时间复杂度,要做一次排序,是不能达…

突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…

1. Array 基础 27 Remove Element 26 Remove Duplicates from Sorted Array 80 Remove Duplicates from Sorted Array II 277 Find the Celebrity 189 Rotate Array 41 First Missing Positive 299 Bulls and Cows 134 Gas Station 118 Pascal's Triangle 很少考 119 Pascal's…

357. Count Numbers with Unique Digits 解题思路: 用arr[i]存放长度为i时,各位互不相同的数字的个数,所以arr[1]=10,arr[2]=9*9.(第一位要为1,第二位与第一位要不同) arr[3] = arr[2]*8,所以arr[i]=arr[i-1]*(10 - (k-1)).之后求和就可以了. int countNumbersWithUniqueDigits(int n) { if (!n) return 1; if (n == 1) retu…

All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…

All LeetCode Questions List 题目汇总 Sorted by frequency of problems that appear in real interviews. Last updated: October 2, 2017Google (214)534 Design TinyURL388 Longest Absolute File Path683 K Empty Slots340 Longest Substring with At Most K Distinct C…