Simple Molecules time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Mad scientist Mike is busy carrying out experiments in chemistry. Today he will attempt to join three atoms into one molecul…

CodeForces - 344B id=46665" style="color:blue; text-decoration:none">Simple Molecules Time Limit: 1000MS   Memory Limit: 262144KB   64bit IO Format: %I64d & %I64u id=46665" class="login ui-button ui-widget ui-state-default…

link:http://codeforces.com/contest/344/problem/B 刚开始想复杂了.一开始就想当然地以为可以有多个点,其实,人家题目要求只有3个点啊! 然后题目就简单了. A.B.C代表原子的化合价 x.y.z代表原子之间的化学键 首先x+y+z一定为偶数,否则不可能有解. 那么可以列出一个三元一次的方程组,由3个方程组成,可以求出唯一解. 判断有解的唯一限制条件是:不能出现负数. #include <cstdlib> #include <cstdio>…

题目链接:http://codeforces.com/problemset/problem/344/B 题目意思:这句话是解题的关键: The number of bonds of an atom in the molecule must be equal to its valence number. 给定三个原子的化学价,规定化学价数等于该原子与另外两个原子所连接的原子键之和. 又一次把简单问题复杂化了.....(以下注释部分读者可以忽略) /* 一开始三重循环枚举,绝对超时(10^6 * 1…

http://codeforces.com/contest/344/problem/B #include <cstdio> #include <cstring> using namespace std; int main() { int a,b,c; ,t2=,t3=; while(scanf("%d%d%d",&a,&b,&c)!=EOF) { bool flag=false; ; i<=a; i++) { t1=i; ) { t…

time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output   Mad scientist Mike is busy carrying out experiments in chemistry. Today he will attempt to join three atoms into one molecule. A molecule c…

#include<bits/stdc++.h> using namespace std; int main() { int a,b,c; scanf("%d%d%d",&a,&b,&c); int ab=a+b-c,bc=b+c-a,ac=a+c-b; if(ab>=0&&bc>=0&&ac>=0&&ab%2==0&&bc%2==0&&ac%2==0)…

这次比赛出的题真是前所未有的水!只用了一小时零十分钟就过了前4道题,不过E题还是没有在比赛时做出来,今天上午我又把E题做了一遍,发现其实也很水.昨天晚上人品爆发,居然排到Rank 55,运气好的话没准能领到T-shirt.除此之外,锁上程序之后,看到一个人数组开小了,我还提交了一个大数据,成功Hack了一次,然后Room排名顿时升到第1. My submissions     # When Who Problem Lang Verdict Time Memory 4474604 Sep 15,…

http://open.sina.com.cn/course/id_1047/ What scientists do is not just collect data and collect facts and stick them in big books,and what's more ,their main job is to talk to each other about what they don't know. They really do care about a kind of…

A. Magnets 模拟. B. Simple Molecules 设12.13.23边的条数,列出三个等式,解即可. C. Rational Resistance 题目每次扩展的电阻之一是1Ω的,所以假设当前的电阻为\(\frac{a}{b}\)会变成\(\frac{a+b}{b}\)或\(\frac{a}{a+b}\),其实就是求gcd的过程. D. Alternating Current 若出现连续两个相同的符号,其实线的方向是不变的,最后就是转化成括号匹配. E. Read Time…