题意:有n堆石子,每次可以将其中一堆分为数量不为0的3堆,或者从其中一堆中拿走若干个,最终拿完的那个人赢. 思路:直接暴力SG状态,然后找出其中的规律,异或一下每一堆的状态就可以了. #include<bits/stdc++.h> using namespace std; typedef long long ll; ;bool flag[maxn]; int sg[maxn]; int getSg(int x){ ) return sg[x]; memset(flag, , sizeof(fl…

题意: 给你n堆石子,你每次只能操作一堆石子 1.拿去任意个,最少1个 2.把这一堆分成两堆,没有要求对半分 解析+代码: 1 //解题思路: 2 //对于一个给定的有向无环图,定义关于图的每个顶点的Sprague-Grundy函数g如下:g(x)=mex{ g(y) | y是x的后继 },这里的g(x)即sg[x] 3 //例如:取石子问题,有1堆n个的石子,每次只能取{1,3,4}个石子,先取完石子者胜利,那么各个数的SG值为多少? 4 //sg[0]=0, 5 //n=1时,可以取走{1}…

SG打表找规律 HDU 5795 题目连接 #include<iostream> #include<cstdio> #include<cmath> #include<algorithm> #include<cstring> using namespace std; #define MAXN 10000 int sg[MAXN],visit[MAXN]; int getsg(int n) { int i,j; ) return sg[n]; mem…

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题意: 有n堆石子,alice先取,每次可以选择拿走一堆石子中的1~x(该堆石子总数) ,也可以选择将这堆石子分成任意的两堆.alice与bob轮流取,取走最后一个石子的人胜利. 思路: 因为数的范围比较大,所以最好通过SG打表的结果找出规律在解. sg(4k+1)=4k+1;sg(4k+2)=4k+2;sg(4k+3)=4k+4; sg(4k)=4k-1; 1 2 4 3 5 6 8 7 Sample Input232 2 323 3 Sample OutputAliceBob SG打表找规律…

A Simple Nim Problem Description   Two players take turns picking candies from n heaps,the player who picks the last one will win the game.On each turn they can pick any number of candies which come from the same heap(picking no candy is not allowed)…

A Simple Nim Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Problem Description Two players take turns picking candies from n heaps,the player who picks the last one will win the game.On each turn they can pick an…

A Simple Nim Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 79    Accepted Submission(s): 48 Problem Description Two players take turns picking candies from n heaps,the player who picks the las…

A Simple Nim 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5795 Description Two players take turns picking candies from n heaps,the player who picks the last one will win the game.On each turn they can pick any number of candies which come from the…

题意:在nim游戏的规则上再增加了一条,即可以将任意一堆分为三堆都不为0的子堆也视为一次操作. 分析:打表找sg值的规律即可. 感想:又学会了一种新的方法,以后看到sg值找不出规律的,就打表即可~ 打表代码如下: #include <stdio.h> #include <algorithm> #include <string.h> #include <set> using namespace std; +]; int main() { sg[] = ; ;i…

打表找SG函数规律. #pragma comment(linker, "/STACK:1024000000,1024000000") #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include<vector> #include<map> #include<set> #include<queue>…

问题描述 Tina Town 是一个善良友好的地方,这里的每一个人都互相关心. Tina有一个球,它的名字叫zball.zball很神奇,它会每天变大.在第一天的时候,它会变大11倍.在第二天的时候,它会变大22倍.在第nn天的时候,它会变大nn倍. zball原来的体积是11.Tina想知道,zball在第n-1n−1天时的体积对nn取模是多大呢? Tina是一个蠢蠢的女孩子,当然不会算啦,所以她请你帮她算出这个答案呢. 输入描述 第一行一个正整数TT,表示数据组数 接下来TT行,每行一个正整…

Nim or not Nim? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 613    Accepted Submission(s): 282 Problem Description Nim is a two-player mathematic game of strategy in which players take turns…

有n堆石子,alice先取,每次可以选择拿走一堆石子中的1~x(该堆石子总数) ,也可以选择将这堆石子分成任意的两堆.alice与bob轮流取,取走最后一个石子的人胜利. 打表代码: #include<iostream> #include<cstdio> #include<cstring> #include<cstdlib> using namespace std; ; int sg[N]; //注意 S数组要按从小到大排序 SG函数要初始化为-1 对于每个…

题意: n*m的棋盘,一枚硬币右上角,每人每次可将硬币移向三个方向之一(一格单位):左边,下边,左下边. 无法移动硬币的人负. 给出n和m,问,先手胜还是后手胜. 数据范围: n, m (0<n,m<=2000) 思路: dp[i][j]=0,说明从(i,j)这个点到时左下角先手败.dp[i][j]=1则先手胜. 然后记忆搜.但是记忆搜会超时. 搜完把整张表打出来,发现规律了,,,,然后,,,代码剩几行了. 代码: ///打表观察 /* int f[2005][2005]; int go(in…

Nim or not Nim? Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 3032 Description Nim is a two-player mathematic game of strategy in which players take turns removing objects from distinct heaps.…

题意:有N堆石子,每堆有s[i]个,Alice和Bob两人轮流取石子,可以从一堆中取任意多的石子,也可以把一堆石子分成两小堆 Alice先取,问谁能获胜 思路:首先观察这道题的数据范围  1 ≤ N ≤ 10^6, 1 ≤ [Si] ≤ 2^31 - 1,很明显数据量太大,所以只能通过打表找规律 打表后发现,如果x%4==0 sg[x]=x-1 ;如果 x%4==3 sg[x]=x+1;如果 其他情况 sg[x]=x; 代码: 打表代码: #include <iostream> #includ…

A Simple Nim Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 980    Accepted Submission(s): 573 Problem Description Two players take turns picking candies from n heaps,the player who picks the l…

题目链接:hdu_5795_A Simple Nim 题意: 有N堆石子,你可以取每堆的1-m个,也可以将这堆石子分成3堆,问你先手输还是赢 题解: 打表找规律可得: sg[0]=0 当x=8k+7时sg[x]=8k+8, 当x=8k+8时sg[x]=8k+7, 其余时候sg[x]=x:(k>=0) #include<cstdio> int main() { int t,n,ans,tp; scanf("%d",&t); while(t--) { scanf(…

Nim or not Nim? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2513    Accepted Submission(s): 1300 Problem Description Nim is a two-player mathematic game of strategy in which players take tur…

Permutation Bo 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5753 Description There are two sequences h1∼hn and c1∼cn. h1∼hn is a permutation of 1∼n. particularly, h0=hn+1=0. We define the expression [condition] is 1 when condition is True,is 0 whe…

Recently kiki has nothing to do. While she is bored, an idea appears in his mind, she just playes the checkerboard game.The size of the chesserboard is n*m.First of all, a coin is placed in the top right corner(1,m). Each time one people can move the…

http://acm.hdu.edu.cn/showproblem.php?pid=4731 就做了两道...也就这题还能发博客了...虽然也是水题 先暴力DFS打表找规律...发现4个一组循环节...尾部特殊判断....然后构造一下... #include <cstdio> #include <string> #include <cstdlib> #include <cstring> #include <iostream> #include &…

Couple doubi 题目链接: http://acm.hust.edu.cn/vjudge/contest/121334#problem/D Description DouBiXp has a girlfriend named DouBiNan.One day they felt very boring and decided to play some games. The rule of this game is as following. There are k balls on th…

Fibonacci Again Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 66450    Accepted Submission(s): 30760 Problem Description There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n)…

HazelFan is given two positive integers a,b, and he wants to calculate amodb. But now he forgets the value of b and only remember the value of a, please tell him the number of different possible results. Input The first line contains a positive integ…

Problem Description Now given two kinds of coins A and B,which satisfy that GCD(A,B)=1.Here you can assume that there are enough coins for both kinds.Please calculate the maximal value that you cannot pay and the total number that you cannot pay. Inp…

Good Luck in CET-4 Everybody! Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4762    Accepted Submission(s): 3058 Problem Description 大学英语四级考试就要来临了,你是不是在紧张的复习?或许紧张得连短学期的ACM都没工夫练习了,反正我知道的Kiki和C…

转载请声明出处:http://www.cnblogs.com/kevince/p/3887827.html    ——By Kevince 首先声明一下,这里的规律指的是循环,即找到最小循环周期. 这么一说大家心里肯定有数了吧,“不就是next数组性质的应用嘛”,没错,正是如此. 在ACM的比赛中有些时候会遇到一些题目,可以或必须通过找出数据的规律来编写代码,这里我们专门来讨论下 如何运用KMP中next数组的性质 来寻找一个长数组中的最小循环周期. 先来看一道题 ZOJ 3785 What d…

题目链接:hdu_5894_hannnnah_j’s Biological Test 题意: 有n个不同的位置围成一个圈,现在要安排m个人坐,每个人至少的间隔为k,问有多少种安排 题解: 先打表找规律,最后发现答案为n*C(n-m*k-1,n-m*k-m)/m 然后这里求组合要预处理一下,逆元也预处理一下 最后还要特判m为1的情况 #include<cstdio> typedef long long ll; ; ; ,},a[maxn],b[maxn]; ll pow_mod(ll a, ll…