You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the first turn to remove th…

Sort a linked list in O(n log n) time using constant space complexity. 排序问题是我们遇到的一个老问题,从大一开始我们就学习了各种排序算法,大部分是基于数组的,比如冒泡排序,插入排序,快速排序等.这其中冒泡排序,插入排序的算法复杂度都是O(n2),插入排序的时间复杂度为O(nlogn).对于这个题目,显然我们不能使用冒泡排序和插入排序,因为这样时间复杂度不满足要求,那么链表适合用快速排序吗?答案是肯定的,链表的结构还是非常方便…

Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note:Given n…

problem 292. Nim Game solution class Solution { public: bool canWinNim(int n) { ; } }; 来generalize一下这道题,当可以拿1-n个石子时,那么个数为(n+1)的整数倍时一定会输,我们试着证明一下这个结论,若当前共有m*(n+1)个石子,那么: 当m=1时,即剩n+1个的时候,肯定会输,因为不管你取1-n中的任何一个数字,另一个人都可以取完. 当m>1时,即有m*(n+1)的时候,不管你先取1-n中的任何…

一天一道LeetCode 从今天开始,调整规律,不按顺序做,从easy开始! 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/nim-game/ Total Accepted: 66290 Total Submissions: 125590 Difficulty: Easy 题目描述 You are playing the following Nim Game with your friend: T…

你和你的朋友,两个人一起玩 Nim游戏:桌子上有一堆石头,每次你们轮流拿掉 1 - 3 块石头. 拿掉最后一块石头的人就是获胜者.你作为先手. 你们是聪明人,每一步都是最优解. 编写一个函数,来判断你是否可以在给定石头数量的情况下赢得游戏. 示例: 输入: 4 输出: false 解释: 如果堆中有 4 块石头,那么你永远不会赢得比赛: 因为无论你拿走 1 块.2 块 还是 3 块石头,最后一块石头总是会被你的朋友拿走. 解析 这是巴什博奕 n=k*(m+1)+r n是要报的数,m是最多能报的数…

题目链接:https://leetcode-cn.com/problems/nim-game/description/ 您和您的朋友,两个人一起玩 Nim游戏:桌子上有一堆石头,每次你们轮流拿掉 1 到 3 块石头. 拿掉最后一块石头的人就是胜利者.由您来开局. 你们两个都是聪明人,相信都有最佳的游戏策略. 请编写一个函数,来判断您是否可以在给定的石头数量的情况下赢得游戏. 比方说,如果堆中有4块石头,那么你永远不会赢得比赛:无论你拿走的是 1块,2块 还是 3块 石头,最后一块石头总是会被你的…

You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the first turn to remove th…

题目描述: 你和你的朋友,两个人一起玩 Nim 游戏:桌子上有一堆石头,每次你们轮流拿掉 1 - 3 块石头. 拿掉最后一块石头的人就是获胜者.你作为先手. 你们是聪明人,每一步都是最优解. 编写一个函数,来判断你是否可以在给定石头数量的情况下赢得游戏. 示例: 输入: 4 输出: false 解释: 如果堆中有 4 块石头,那么你永远不会赢得比赛:   因为无论你拿走 1 块.2 块 还是 3 块石头,最后一块石头总是会被你的朋友拿走. 思路分析: 如果堆中石头的数量 nn 不能被 44 整除…

344. Reverse String /** * @param {string} s * @return {string} */ var reverseString = function(s) { return s.split("").reverse().join(""); }; 292. Nim Game 尼姆游戏还是很有意思的,这题有很多地方可以深入理解 /** * @param {number} n * @return {boolean} */ var ca…

lc 292 Nim Game 292 Nim Game You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will tak…

变型:如果是最后拿走所有石子那个人输,则f[0] = true 394. Coins in a Line dp[n]表示n个石子,先手的人,是必胜还是必输.拿1个石子,2个石子之后都是必胜,则当前必败:拿1个石子,2个石子之后都是必败,则当前必胜:如果拿1个石子,2个石子之后有必败,则当前必胜. class Solution { public: /** * @param n: An integer * @return: A boolean which equals to true if the…

292. Nim 游戏 你和你的朋友,两个人一起玩 Nim 游戏:桌子上有一堆石头,每次你们轮流拿掉 1 - 3 块石头. 拿掉最后一块石头的人就是获胜者.你作为先手. 你们是聪明人,每一步都是最优解. 编写一个函数,来判断你是否可以在给定石头数量的情况下赢得游戏. 示例: 输入: 4 输出: false 解释: 如果堆中有 4 块石头,那么你永远不会赢得比赛: 因为无论你拿走 1 块.2 块 还是 3 块石头,最后一块石头总是会被你的朋友拿走. 巴什博奕,n%(m+1)!=0时,先手总是会赢的…

Question 292. Nim Game Solution 思路:试着列举一下,就能发现一个n只要不是4的倍数,就能赢. n 是否能赢 1 true 2 true 3 true 4 false 不论删除几,对方都能一把赢 5 true 删除1,还剩4,对方先手,对方输 6 true 删除2,还剩4,对方先手,对方输 7 true 删除3,还剩4,对方先手,对方输 8 false 不论删除几,都能被对方造成还剩4,已方先手,我们就输 9 true 10 true Java实现: public…

292. Nim Game You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the first tur…

博客搬至blog.csgrandeur.com,cnblogs不再更新. 新的题解会更新在新博客:http://blog.csgrandeur.com/2014/01/15/LeetCode-OJ-Solution/ ———————————————————————————————————————— ———————————————————————————————————————— LeetCode OJ 题解 LeetCode OJ is a platform for preparing tech…

Problem Link: http://oj.leetcode.com/problems/interleaving-string/ Given s1, s2, s3, find whether s3 is formed by the interleaving of s1 and s2. For example, Given: s1 = "aabcc", s2 = "dbbca", When s3 = "aadbbcbcac", return t…

Problem link: http://oj.leetcode.com/problems/reverse-words-in-a-string/ Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". LeetCode OJ supports Python now! The s…

一直没有系统地学习过算法,不过算法确实是需要系统学习的.大二上学期,在导师的建议下开始学习数据结构,零零散散的一学期,有了链表.栈.队列.树.图等的概念.又看了下那几个经典的算法——贪心算法.分治算法.动态规划以及回溯算法.不过,都是知其一不知其二的一知半解.到最后,发现学到了一堆的一知半解,在学校课程开这门课时,却又是不得不再学一遍.学一样东西,又不全心全意地主动去把它学好,到最后只是花费了时间,却没真真学到东西.所以,不求学识有多广,但求所学的都精. 一个偶然的机会,让我在网上找到了一本社区…

292. Nim Game(C++) You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the firs…

Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another comput…

常泡LC的朋友知道LC是不提供代码打包下载的,不像一般的OJ,可是我不备份代码就感觉不舒服- 其实我想说的是- 我自己写了抓取个人提交代码的小工具,放在GitCafe上了- 不知道大家有没有兴趣 https://gitcafe.com/aaronzhou/ ... ssion 拿Java写的,也打了一个包,本地有JRE环境就能运行,欢迎拍砖 抓取 LeetCode OJ 个人提交的代码 Gradle 构建项目 HttpClient.jsoup 抓取.解析网页 使用说明 进入release文件夹…

题目: Given a 2D binary matrix filled with 0's and 1's, find the largest square containing all 1's and return its area. For example, given the following matrix: 1 0 1 0 0 1 0 1 1 1 1 1 0 0 1 0 Return 4. 题目链接:https://leetcode.com/problems/maximal-square…

Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. 给定一个整数,将他转换到罗马字符.同样这里的罗马字符不会超过1000(M),PS:关于罗马字符的介绍看我的这篇文章 :LeetCode OJ:Roman to Integer(转换罗马字符到整数) 这里的大体思路是这样的,例如对于罗马字符952来说,起答题的可以分成三个组成部分, 就…

Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another comput…

292. Nim游戏 class Solution(object): def canWinNim(self, n): """ :type n: int :rtype: bool """ return n % 4 != 0 # return not (n%4==0) """ 你和你的朋友,两个人一起玩 Nim游戏:桌子上有一堆石头,每次你们轮流拿掉 1 - 3 块石头. 拿掉最后一块石头的人就是获胜者.你作为先手. 你…

You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the first turn to remove th…

Problem: You are playing the following Nim Game with your friend: There to stones. The one who removes the last stone will be the winner. You will take the first turn to remove the stones. Both of you are very clever and have optimal strategies for t…

问题描述: You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the first turn to rem…