问题: Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Single Number I 升级版,一个数组中其它数出现了…
判断数组中是否有重复元素,最容易想到的方法是使用2重循环,逐个遍历,比较,但是这个是最慢,最笨的方法,百度得出了更好的方法. var ary = new Array("111","22","33","111"); var nary=ary.sort(); for(var i=0;i<ary.length;i++){ if (nary[i]==nary[i+1]){ alert("数组重复内容:"+na…