1133 Splitting A Linked List(25 分) Given a singly linked list, you are supposed to rearrange its elements so that all the negative values appear before all of the non-negatives, and all the values in [0, K] appear before all those greater than K. The…
Given a singly linked list, you are supposed to rearrange its elements so that all the negative values appear before all of the non-negatives, and all the values in [0, K] appear before all those greater than K. The order of the elements inside each…
Given a singly linked list, you are supposed to rearrange its elements so that all the negative values appear before all of the non-negatives, and all the values in [0, K] appear before all those greater than K. The order of the elements inside each…
题目 Given a singly linked list, you are supposed to rearrange its elements so that all the negative values appear before all of the non-negatives, and all the values in [0, K] appear before all those greater than K. The order of the elements inside ea…
题意:把链表按规则调整,使小于0的先输出,然后输出键值在[0,k]的,最后输出键值大于k的. 思路:利用vector<Node> v,v1,v2,v3.遍历链表,把小于0的push到v1中,把[0,k]的push到v2中,把大于k的push到v3中,最后把v1,2,3中的按顺序push到v中,在顺序输出v就好了.[注意点]:给出的n个结点不一定都是链表的结点,我在第一遍做的时候,在最后遍历v输出结果时,for循环写成了 ;i<n;i++) ,因为我想链表的结点个数不就是n嘛,结果有一个测…
1133. Splitting A Linked List (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Given a singly linked list, you are supposed to rearrange its elements so that all the negative values appear before all of the non-negatives, and…
Source: PAT A1133 Splitting A Linked List (25 分) Description: Given a singly linked list, you are supposed to rearrange its elements so that all the negative values appear before all of the non-negatives, and all the values in [0, K] appear before al…
Splitting A Linked List PAT-1133 本题一开始我是完全按照构建链表的数据结构来模拟的,后来发现可以完全使用两个vector来解决 一个重要的性质就是位置是相对不变的. #include<iostream> #include<cstring> #include<string> #include<algorithm> #include<cstdio> #include<sstream> #include<…
Cutting an integer means to cut a K digits long integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A…
1074 Reversing Linked List (25)(25 分) Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K = 3, then you must output 3→2→1→6→5→4; if K = 4, you mus…