200. 岛屿数量 给定一个由 '1'(陆地)和 '0'(水)组成的的二维网格,计算岛屿的数量.一个岛被水包围,并且它是通过水平方向或垂直方向上相邻的陆地连接而成的.你可以假设网格的四个边均被水包围. 示例 1: 输入: 11110 11010 11000 00000 输出: 1 示例 2: 输入: 11000 11000 00100 00011 输出: 3 PS: 循环得时候把1变成2,防止重复计算一个岛,并且提高效率 class Solution { public int numIsland…

岛屿数量 给你一个由 '1'(陆地)和 '0'(水)组成的的二维网格,请你计算网格中岛屿的数量. 岛屿总是被水包围,并且每座岛屿只能由水平方向和/或竖直方向上相邻的陆地连接形成. 此外,你可以假设该网格的四条边均被水包围. 示例 1: 输入: 11110 11010 11000 00000 输出: 1 示例 2: 输入: 11000 11000 00100 00011 输出: 3 解释: 每座岛屿只能由水平和/或竖直方向上相邻的陆地连接而成. 题解 利用dfs逐个标记 class Solutio…

习题地址 https://leetcode-cn.com/problems/number-of-islands/ 给定一个由 '1'(陆地)和 '0'(水)组成的的二维网格,计算岛屿的数量.一个岛被水包围,并且它是通过水平方向或垂直方向上相邻的陆地连接而成的.你可以假设网格的四个边均被水包围. 示例 1: 输入: 输出: 示例 2: 输入: 输出: 解法 广度遍历或者使用并查集 这里使用并查集.注意将二维数组转换为一维的方法 代码 class UnionFind { public: vector…

Leetcode之深度优先搜索(DFS)专题-200. 岛屿数量(Number of Islands) 深度优先搜索的解题详细介绍,点击 给定一个由 '1'(陆地)和 '0'(水)组成的的二维网格,计算岛屿的数量.一个岛被水包围,并且它是通过水平方向或垂直方向上相邻的陆地连接而成的.你可以假设网格的四个边均被水包围. 示例 1: 输入: 11110 11010 11000 00000 输出: 1 示例 2: 输入: 11000 11000 00100 00011 输出: 3 分析:这题同样是求连…

Leetcode 200 岛屿的数量: DFS利用函数调用栈保证了检索顺序, BFS则需要自己建立队列,把待检索对象按规则入队. class Solution { // DFS解法,8ms/10.7MB,99.7% / 92% public: /** * row,col: 坐标,以0开始. * 用row和col,而不是x,y. 否则容易写成grid[x][y],顺序不对!! */ void dfs_set_zero(vector<vector<char>>& grid, i…

695. 岛屿的最大面积 题目 给定一个包含了一些 0 和 1的非空二维数组 grid , 一个 岛屿 是由四个方向 (水平或垂直) 的 1 (代表土地) 构成的组合.你可以假设二维矩阵的四个边缘都被水包围着. 找到给定的二维数组中最大的岛屿面积.(如果没有岛屿,则返回面积为0.) 题解 dfs/bfs. 这题dfs简练一点. 注意是先判边界再判点为1,否则可能造成数组越界. 相关 dfs用递归,bfs用队列. bfs中注意计数和置已访问的点为0是入队时做,否则会出现同一层两个点都可达一个有效点…

题目描述: 给定一个由 '1'(陆地)和 '0'(水)组成的的二维网格,计算岛屿的数量.一个岛被水包围,并且它是通过水平方向或垂直方向上相邻的陆地连接而成的.你可以假设网格的四个边均被水包围. 示例 1: 输入: 11110 11010 11000 00000 输出: 1 示例 2: 输入: 11000 11000 00100 00011 输出: 3 思路分析:题解和示例图来自:liweiwei1419 说明:以下介绍的算法,除了并查集以外,DFS 和 BFS 都属于很基础的算法内容,也非常好理…

Given a 2d grid map of '1's (land) and '0's (water), count the number of islands. An island is surrounded by water and is formed by connecting adjacent lands horizontally or vertically. You may assume all four edges of the grid are all surrounded by…

1.题目描述 给定一个由 '1'(陆地)和 '0'(水)组成的的二维网格,计算岛屿的数量.一个岛被水包围,并且它是通过水平方向或垂直方向上相邻的陆地连接而成的.你可以假设网格的四个边均被水包围. 示例 1: 输入: 11110 11010 11000 00000 输出: 1 示例 2: 输入: 11000 11000 00100 00011 输出: 3 2.解题思路 算法核心框架:深度搜索+递归 深度搜索:整个岛屿是一个“二维矩阵”(vector<vectro<char>>),使用…

给定一个由 '1'(陆地)和 '0'(水)组成的的二维网格,计算岛屿的数量.一个岛被水包围,并且它是通过水平方向或垂直方向上相邻的陆地连接而成的.你可以假设网格的四个边均被水包围. 示例 1: 输入: 11110110101100000000 输出: 1 示例 2: 输入: 11000110000010000011 输出: 3 和之前的DFS寻找最短路径不同,这道题没有了终点,所以不需要我们回退时,将点设置为可行.首先找到一个可行点,然后将这个可行点可以到达的地方全部感染,这就是一个岛.我们再搜…

题目描述 给定一个由 '1'(陆地)和 '0'(水)组成的的二维网格,计算岛屿的数量.一个岛被水包围,并且它是通过水平方向或垂直方向上相邻的陆地连接而成的.你可以假设网格的四个边均被水包围. 示例 1: 输入: 11110 11010 11000 00000 输出: 1 示例 2: 输入: 11000 11000 00100 00011 输出: 3 解题思路 深度优先搜索,访问到以个为‘1’的点首先将其置‘0’,并将岛屿个数加一,然后分别按照右-下-左-上的顺序递归搜索矩阵并置‘1’为‘0’.…

主要考察图搜索: 方法一:染色法,时间O(mn) 遍历一遍,再通过BFS或DFS将所有临近岛屿染色,使用dfs时将numIslands中的bfs换成dfs即可: /***** 遍历所有的点: 只要遇见陆地(1),投放1枚原子弹,爆炸冲击波以BFS或DFS的形式向外扩散,使得自身及所有相邻区域全部夷为平地: 最终遍历结束,原子弹使用数目即为岛屿次数 *****/ class Solution { public: vector<vector<,},{,},{,},{,-}}; int numIsl…

695. 岛屿的最大面积 给定一个包含了一些 0 和 1 的非空二维数组 grid . 一个 岛屿 是由一些相邻的 1 (代表土地) 构成的组合,这里的「相邻」要求两个 1 必须在水平或者竖直方向上相邻.你可以假设 grid 的四个边缘都被 0(代表水)包围着. 找到给定的二维数组中最大的岛屿面积.(如果没有岛屿,则返回面积为 0 .) 示例 1: [[0,0,1,0,0,0,0,1,0,0,0,0,0], [0,0,0,0,0,0,0,1,1,1,0,0,0], [0,1,1,0,1,0,0,…

463. 岛屿的周长 给定一个包含 0 和 1 的二维网格地图,其中 1 表示陆地 0 表示水域. 网格中的格子水平和垂直方向相连(对角线方向不相连).整个网格被水完全包围,但其中恰好有一个岛屿(或者说,一个或多个表示陆地的格子相连组成的岛屿). 岛屿中没有"湖"("湖" 指水域在岛屿内部且不和岛屿周围的水相连).格子是边长为 1 的正方形.网格为长方形,且宽度和高度均不超过 100 .计算这个岛屿的周长. 示例 : 输入: [[0,1,0,0], [1,1,1,0…

题目: 给定一个由 '1'(陆地)和 '0'(水)组成的的二维网格,计算岛屿的数量.一个岛被水包围,并且它是通过水平方向或垂直方向上相邻的陆地连接而成的.你可以假设网格的四个边均被水包围. Given a 2d grid map of '1's (land) and '0's (water), count the number of islands. An island is surrounded by water and is formed by connecting adjacent lan…

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