Stars Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 15951    Accepted Submission(s): 5945 Problem Description Astronomers often examine star maps where stars are represented by points on a pla…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1541 题目意思:有 N 颗星星,每颗星星都有各自的等级.给出每颗星星的坐标(x, y),它的等级由所有比它低层(或者同层)的或者在它左手边的星星数决定.计算出每个等级(0 ~ n-1)的星星各有多少颗. 我只能说,题目换了一下就不会变通了,泪~~~~ 星星的分布是不是很像树状数组呢~~~没错,就是树状数组题来滴! 按照题目输入,当前星星与后面的星星没有关系.所以只要把 x 之前的横坐标加起来就可以了…

Problem Description Astronomers often examine star maps where stars are represented by points on a plane and each star has Cartesian coordinates. Let the level of a star be an amount of the stars that are not higher and not to the right of the given…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1541 思路:要求求出不同等级的星星的个数,开始怎么也想不到用树状数组,看完某些大神的博客之后才用树状数组写的,搞了好久才懂得数组的更新过程 #include<cstdio> #include<iostream> #include<algorithm> #include<math.h> #include<string.h> #include<ve…

一開始想,总感觉是DP,但是最后什么都没想到.还暴力的交了一发. 然后開始写线段树,结果超时.感觉自己线段树的写法有问题.改天再写.先把树状数组的写法贴出来吧. ~~~~~~~~~~~~~~~~~~~~~~~~ 树状数组不懂的去看刘汝佳的大白书,那个图画得非常清楚. 题目大意:星星的坐标以y递增的顺序给出,这些点的左下方的点数代表这个点的级数,问0~N-1的级数有多少个?事实上y根本木实用. 题目链接:http://poj.org/problem?id=2352 http://acm.hdu.e…

题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=1541 题意 求每个等级的星星有多少个 当前这个星星的左下角 有多少个 星星 它的等级就是多少 和它同一水平线的左边的星星 以及 同一竖直线的下边的星星也算在内 思路 因为题目给出的x y 坐标 是按照 以 y 为第一关键词 x 为第二关键词 排序后给出的 那么 对于当前的星星来说,在它之前给出的星星中,都是在它下边的 所以 我们就可以不用管 Y 坐标 只用X 坐标 形成一个序列 就是求这个序列的 所…

Problem Description Astronomers often examine star maps where stars are represented by points on a plane and each star has Cartesian coordinates. Let the level of a star be an amount of the stars that are not higher and not to the right of the given…

Stars Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 41521   Accepted: 18100 Description Astronomers often examine star maps where stars are represented by points on a plane and each star has Cartesian coordinates. Let the level of a st…

 Problem Description Astronomers often examine star maps where stars are represented by points on a plane and each star has Cartesian coordinates. Let the level of a star be an amount of the stars that are not higher and not to the right of the giv…

题意:求坐标0到x间的点的个数 思路:线段树,主要是转化,根据题意的输入顺序,保证了等级的升序,可以直接求出和即当前等级的点的个数,然后在把这个点加入即可. 注意:线段树下标从1开始,所以把所有的x加1存储. #include<iostream> #include<stdio.h> #include<string.h> using namespace std; #define MAXN 32005 #define MAXL 15005 int ans; int lev[…