假设有两个字符串A.B,要判断它们是否为旋转词,只需构造一个"A+A"字符串,再与B比较,若B为A的旋转词,则使用KMP算法是可以得到结果的 代码如下: import java.util.*; public class test { public static boolean chkRotation(String A, String B) { if(A.length()!=B.length()) return false; String buf =new String(A+A); in…
字符串匹配是字符串的一种基本操作:给定一个长度为 M 的文本和一个长度为 N 的模式串,在文本中找到一个和该模式相符的子字符串,并返回该字字符串在文本中的位置. KMP 算法,全称是 Knuth-Morris-Pratt 算法,以三个发明者命名,开头的那个K就是著名科学家 Donald Knuth .KMP 算法的关键是求 next 数组.next 数组的长度为模式串的长度.next 数组中每个值代表模式串中当前字符前面的字符串中,有多大长度的相同前缀后缀. Boyer-Moore 算法在实际应…
Spy Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 204 Accepted Submission(s): 96 Problem Description “Be subtle! Be subtle! And use your spies for every kind of business. ” — Sun Tzu “A sp…
Period Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2398 Accepted Submission(s): 1187 Problem Description For each prefix of a given string S with N characters (each character has an ASCII…
Count the string Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3797 Accepted Submission(s): 1776 Problem Description It is well known that AekdyCoin is good at string problems as well as nu…
Kmp: 算法定义借鉴wikipedia: http://en.wikipedia.org/wiki/Knuth%E2%80%93Morris%E2%80%93Pratt_algorithm#KMP_algorithm 代码: import java.util.Scanner; public class Main { public static void main(String[] argv){ Main u = new Main(); Scanner in = new Scanner(Syst…
Clairewd’s message Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2929 Accepted Submission(s): 1132 Problem Description Clairewd is a member of FBI. After several years concealing in BUPT, s…