题目描述 Farmer John's N cows (1 <= N <= 10,000) are conveniently numbered 1..N. Each cow i takes T(i) units of time to milk. Unfortunately, some cows must be milked before others, owing to the layout of FJ's barn. If cow A must be milked before cow B,…
题目描述 Farmer John has N cows that need to be milked (1 <= N <= 10,000), each of which takes only one unit of time to milk. Being impatient animals, some cows will refuse to be milked if Farmer John waits too long to milk them. More specifically, cow…
洛谷题目链接:[USACO06DEC]牛奶模式Milk Patterns 题目描述 Farmer John has noticed that the quality of milk given by his cows varies from day to day. On further investigation, he discovered that although he can't predict the quality of milk from one day to the next,…
P2949 [USACO09OPEN]工作调度Work Scheduling 题目描述 Farmer John has so very many jobs to do! In order to run the farm efficiently, he must make money on the jobs he does, each one of which takes just one time unit. His work day starts at time 0 and has 1,000…
P2949 [USACO09OPEN]工作调度Work Scheduling 题目描述 Farmer John has so very many jobs to do! In order to run the farm efficiently, he must make money on the jobs he does, each one of which takes just one time unit. His work day starts at time 0 and has 1,000…
Description Farmer John has N cows that need to be milked (1 <= N <= 10,000), each of which takes only one unit of time to milk. Being impatient animals, some cows will refuse to be milked if Farmer John waits too long to milk them. More specificall…
题目链接 \(Click\) \(Here\) 水题.利用\(Height\)的性质维护一个单调栈即可. #include <bits/stdc++.h> using namespace std; #define LL long long const int N = 1000010; int n, m = 1000000, q, s[N], sa[N], tp[N]; int rk[N], _rk[N], bin[N], height[N]; void base_sort () { for (…
传送门 一道简单的字符串.这里收集了几种经典做法: SAM,不想写. 后缀数组+二分,不想写 后缀数组+单调队列,不想写 hash+二分,for循哈希,天下无敌!于是妥妥的hash 代码如下: #include<bits/stdc++.h> #define N 20005 #define Base 20001 using namespace std; inline int read(){ int ans=0; char ch=getchar(); while(!isdigit(ch))ch=g…
link 这是一道后缀匹配的模板题 我们只需要将height算出来 然后二分一下答案就可以了 #include<cstdio> #include<algorithm> #include<iostream> #include<cstring> using namespace std; const int maxn=1010000; int data[maxn]; int rank[maxn]; int tot[maxn]; int sa[maxn]; int…
题目描述 Farmer John has so very many jobs to do! In order to run the farm efficiently, he must make money on the jobs he does, each one of which takes just one time unit. His work day starts at time 0 and has 1,000,000,000 time units (!). He currently c…