import functools # Definition for a binary tree node. # class TreeNode(object): # def __init__(self, x): # self.val = x # self.left = None # self.right = None @functools.lru_cache() class Solution(object): def rangeSumBST(self, root, L, R): ""&q…

https://leetcode-cn.com/problems/range-sum-of-bst/ 二叉树中序遍历 二叉搜索树性质:一个节点大于所有其左子树的节点,小于其所有右子树的节点 /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ clas…

problem 938. Range Sum of BST 参考 1. Leetcode_easy_938. Range Sum of BST; 完…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 日期 题目地址:https://leetcode.com/contest/weekly-contest-110/problems/range-sum-of-bst/ 题目描述 Given the root node of a binary search tree, return the sum of values of all nodes wi…

Given the root node of a binary search tree, return the sum of values of all nodes with value between L and R (inclusive). The binary search tree is guaranteed to have unique values. Example 1: Input: root = [10,5,15,3,7,null,18], L = 7, R = 15 Outpu…

771. Jewels and Stones (Easy)# You're given strings J representing the types of stones that are jewels, and S representing the stones you have. Each character in S is a type of stone you have. You want to know how many of the stones you have are also…

Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. Example: Given nums = [-2, 0, 3, -5, 2, -1] sumRange(0, 2) -> 1 sumRange(2, 5) -> -1 sumRange(0, 5) -> -3 Note: You may assume that the array do…

Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2). The above rectangle (with the red border) is defined by (row1, col1) = (2, 1) and (row2, co…

Range Sum Query - Mutable 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/range-sum-query-mutable/description/ Description Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) functi…

Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: Given nums = [1, 3, 5] sumRange(0, 2) -> 9 update(1, 2…

原题链接在这里:https://leetcode.com/problems/range-sum-query-2d-mutable/ 题目: Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2). The above rectangle (…

303. Range Sum Query - Immutable class NumArray { private: vector<int> v; public: NumArray(vector<int> &nums) { int n = nums.size(); v = vector<int>(n + 1); int sum = 0; for (int i = 1; i <= n; ++i) { sum += nums[i - 1]; v[i] = su…

这是悦乐书的第359次更新,第386篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第221题(顺位题号是938).给定二叉搜索树的根节点,返回节点值在[L,R]之间的所有节点的值的总和.二叉搜索树的节点值唯一.例如: 输入:root = [10,5,15,3,7,null,18],L = 7,R = 15 输出:32 输入:root = [10,5,15,3,7,13,18,1,null,6],L = 6,R = 10 输出:23 注意: 树中的节点数最多为1000…

1.原题: https://leetcode.com/problems/range-sum-of-bst/ Given the root node of a binary search tree, return the sum of values of all nodes with value between L and R (inclusive). The binary search tree is guaranteed to have unique values. Input: root =…

问题描述:给定一序列,求任意区间(i, j)的元素和:修改任意一元素,实现快速更新 树状数组 树状数组的主要特点是生成一棵树,树的高度为logN.每一层的高度为k,分布在这一层的序列元素索引的二进制表达有个共同的特点,就是最低二次幂为k. 子树间有很强的联系,即,给定一序列元素索引i,可以推知该元素所在节点C[i]的父节点C[p],p=i+2^k,其中k=i & (i ^ (i-1)),以及该元素所在子树的前一子树的根节点p=i-2^k. 子树间的联系可以很方便地用于求前n个元素的和,即找到所有…

问题: Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. Example: Given nums = [-2, 0, 3, -5, 2, -1] sumRange(0, 2) -> 1 sumRange(2, 5) -> -1 sumRange(0, 5) -> -3 Note: You may assume that the arra…

Given the root node of a binary search tree, return the sum of values of all nodes with value between L and R (inclusive). The binary search tree is guaranteed to have unique values. Example 1: Input: root = [10,5,15,3,7,null,18], L = 7, R = 15 Outpu…

Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: Given nums = [1, 3, 5] sumRange(0, 2) -> 9 update(1, 2…

Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2). The above rectangle (with the red border) is defined by (row1, col1) = (2, 1) and (row2, co…

Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. Example: Given nums = [-2, 0, 3, -5, 2, -1] sumRange(0, 2) -> 1 sumRange(2, 5) -> -1 sumRange(0, 5) -> -3 Note: 1: You may assume that the array…

题意:查询一个数组在(i,j]范围内的元素的和. 思路非常简单,做个预处理,打个表就好 拓展:可以使用树状数组来完成该统计,算法复杂度为(logn),该数据结构强力的地方是实现简单,而且能完成实时更新以及上面的统计和 class NumArray { public: vector<int> sum; NumArray(vector<int> &nums) { sum.push_back(); ; i< nums.size(); ++i){ int m = sum[i]…

题目描述: Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. Example: Given nums = [-2, 0, 3, -5, 2, -1] sumRange(0, 2) -> 1 sumRange(2, 5) -> -1 sumRange(0, 5) -> -3 Note: You may assume that the ar…

Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: Given nums = [1, 3, 5] sumRange(0, 2) -> 9 update(1, 2…

Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: Given nums = [1, 3, 5] sumRange(0, 2) -> 9 update(1, 2…

Problem: Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: Given nums = [1, 3, 5] sumRange(0, 2) -> 9 up…

题目: Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. Example: Given nums = [-2, 0, 3, -5, 2, -1] sumRange(0, 2) -> 1 sumRange(2, 5) -> -1 sumRange(0, 5) -> -3 Note: You may assume that the arra…

题目: Given an integer array nums, find the sum of the elements between indices iand j (i ≤ j), inclusive. Example: Given nums = [-2, 0, 3, -5, 2, -1] sumRange(0, 2) -> 1 sumRange(2, 5) -> -1 sumRange(0, 5) -> -3 Note: You may assume that the array…

翻译 给定一个整型数组nums,找出在索引i到j(i小于等于j)之间(包含i和j)的全部元素之和. 比如: 给定nums = [-2,0,3,-5,2,-1] sumRange(0, 2) -> 1 sumRange(2, 5) -> -1 sumRange(0, 5) -> -3 批注: 你能够假定这个数组不会改变. 这里会有非常多次对sumRange函数的调用. 原文 Given an integer array nums, find the sum of the elements…

Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: Given nums = [1, 3, 5] sumRange(0, 2) -> 9 update(1, 2…

Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2). The above rectangle (with the red border) is defined by (row1, col1) = (2, 1) and (row2, co…