作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 字典+最大公约数 日期 题目地址:https://leetcode.com/problems/max-points-on-a-line/description/ 题目描述 Given n points on a 2D plane, find the maximum number of points that lie on the same strai…

Max Points on a Line Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. SOLUTION 1: 全部的点扫一次,然后计算每一个点与其它点之间的斜率. 创建一个MAP, KEY-VALUE是 斜率:线上的点的数目. 另外,注意重合的点,每次都要累加到每一条线上. 注意: 1. k = 0 + (double)(points[i].…

Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. 解题思路: 本题主要需要考虑到斜线的情况,可以分别计算出过points[i]直线最多含几个点,然后算出最大即可,由于计算points[i]的时候,前面的点都计算过了,所以不需要把前面的点考虑进去,所以问题可以转化为过points[i]的直线最大点的个数,解题思路是用一个HashMap储存斜率,遍历p…

Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. Example 1: Input: [[1,1],[2,2],[3,3]] Output: 3 Explanation: ^ | | o | o | o +-------------> 0 1 2 3 4 Example 2: Input: [[1,1],[3,2],[5,3],[4,1],[2,3…

Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. 给一个由n个点组成的2D平面,找出最多的同在一条直线上的点的个数. 共线点的条件是斜率一样,corn case:点相同:x坐标相同. Java: public class Solution { public int maxPoints(Point[] points) { int res = 0; f…

Given n points on a 2D plane, find the maximum number of points that lie on the same straight line.  求二维平面上n个点中,最多共线的点数.     1.比较直观的方法是,三层循环,以任意两点划线,判断第三个点是否在这条直线上.   比较暴力   2.使用map来记录每个点的最大数目.   /** * Definition for a point. * class Point { * int x;…

Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. /** * Definition for a point. * struct Point { * int x; * int y; * Point() : x(0), y(0) {} * Point(int a, int b) : x(a), y(b) {} * }; */ class Solutio…

Max Points on a Line Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. 点和方向确定一条直线. 需要两重循环,第一重循环遍历起始点a,第二重循环遍历剩余点b. a和b如果不重合,就可以确定一条直线. 对于每个点a,构建 斜率->点数 的map. (1)b与a重合,以a起始的所有直线点数+1 (用dup统一相加) (2)b与a不重…

Max Points on a Line 题目描述: Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. 解题思路: 1.首先由这么一个O(n^3)的方法,也就是算出每条线的方程(n^2),然后判断有多少点在每条线上(N).这个方法肯定是可行的,只是复杂度太高2.然后想到一个O(N)的,对每一个点,分别计算这个点和其他所有点构成的斜率,具有相同斜率最…

Max Points on a Line Submission Details 27 / 27 test cases passed. Status: Accepted Runtime: 472 ms Submitted: 0 minutes ago Submitted Code Language: java   Edit Code         /** * Definition for a point. * class Point { * int x; * int y; * Point() {…