HDU-6187.DestroyWalls(最大生成树)】的更多相关文章

HDU 6187 Destroy Walls (思维,最大生成树) Destroy Walls *Time Limit: 8000/4000 MS (Java/Others) Memory Limit: 132768/132768 K (Java/Others) Total Submission(s): 1784 Accepted Submission(s): 692 * Problem Description Long times ago, there are beautiful histor…
Destroy Walls Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 132768/132768 K (Java/Others) Total Submission(s): 1774    Accepted Submission(s): 689 Problem Description Long times ago, there are beautiful historic walls in the city. These wal…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=6187 题意:有一个V个结点M条边的带边权无向平面图,有一个人在一个区域,要拆一些墙使得他可以到达任意一个区域,问最小花费. 解法: #include <bits/stdc++.h> using namespace std; const int maxn = 100010; const int maxm = 200010; struct edge{ int u,v,w; edge(){} bool…
http://acm.hdu.edu.cn/showproblem.php? pid=4786 Fibonacci Tree Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1733    Accepted Submission(s): 543 Problem Description Coach Pang is interested i…
Pseudoforest Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 1705    Accepted Submission(s): 653 Problem Description In graph theory, a pseudoforest is an undirected graph in which every conne…
Destroy Walls Long times ago, there are beautiful historic walls in the city. These walls divide the city into many parts of area. Since it was not convenient, the new king wants to destroy some of these walls, so he can arrive anywhere from his cast…
Pseudoforest Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2351    Accepted Submission(s): 910 Problem Description In graph theory, a pseudoforest is an undirected graph in which every connec…
链接:http://acm.hdu.edu.cn/showproblem.php?pid=4786 题意:有N个节点(1 <= N <= 10^5),M条边(0 <= M <= 10^5).当中一部分边被染成了黑色,剩下的边是白色,问能不能建立一棵树,树中有斐波那契数个白色边. 思路:用克鲁斯卡尔建三次树,第一是用全部边建树.推断能否建成一棵树,第二次用黑边建树,最多能够用到x条黑边(不成环),n-1-x就是最少须要用的白边的数量,第三次用白边建树,最多能够用到y条白边.假设在[y…
好吧这个题没什么可说的,有点.... 一开始还和一位大佬在讨论,会不会有多余的边,后面看了题发现没有多于的边和自环,所以之间一波最大生成树把最大的边去掉,把最小的边推倒就行了. #include <cstdio> #include <cstring> #include <algorithm> using namespace std; + , maxm = + ; int n, m, ans, head[maxn]; bool vis[maxm]; struct Edge…
#include <cstdio> #include <cstring> #include <vector> #include <algorithm> using namespace std; ; int n, m; struct node { int u, v, c; }g[maxn]; long long ans; int fa[maxn]; int ff[maxn]; int ee[maxn]; bool cmp(node a, node b){ re…