1675: Morse Code 时间限制: 2 Sec  内存限制: 128 MB提交: 73  解决: 33[提交][状态][讨论版] 题目描述 摩尔斯电码(英语:Morse Code)是一种时通时断的信号代码,通过不同的排列顺序来表达不同的英文字母.数字和标点符号.是由美国人萨缪尔·摩尔斯在1836年发明.                                                                                            …

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述: 题目大意 解题方法 set + map set + 字典 日期 题目地址:https://leetcode.com/problems/unique-morse-code-words/description/ 题目描述: International Morse Code defines a standard encoding where each letter is m…

morse code,摩斯电码,是一种时通时断的信号代码,通过不同的排列顺序来表达不同的英文字母.数字和标点符号. 摩斯电码,是一种早期的数字化通信形式,但是它不同于现代只使用0和1两种状态的二进制代码,它的代码包括5种: 点.划.点和划之间的停顿.每个字符间短的停顿(在点和划之间).每个词之间中等的停顿以及句子之间长的停顿. 下图为morse code的密码本 通过密码本,我们可以写1个测试程序 懂了这些,morse code基本入门了. 接着,说一下电报机原理 首先,电报机是由发报机与收报机…

Oil Deposits Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 8274 Accepted Submission(s): 4860 Problem Description The GeoSurvComp geologic survey company is responsible for detecting underground…

摩尔斯电码,在早期的"生产斗争"生活中,扮演了很重要的角色,作为一种信息编码标准,摩尔斯电码拥有其他编码方案无法超越的长久生命.摩尔斯电码在海事通讯中被作为国际标准一直使用到1999年.不过随着科技的发展,最终还是倒在了历史的车轮下(PS:等等,为何这么熟悉??观众:好一片根正苗红的*文啊,啊啊啊啊),1997年,当法国海军停止使用摩尔斯电码时,发送的最后一条消息是:“所有人注意,这是我们在永远沉寂之前最后的一声呐喊!”. 任何关于Morse code可拓展的咨询,请移步维基百科:摩尔…

Pet Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 535 Accepted Submission(s): 258 Problem Description One day, Lin Ji wake up in the morning and found that his pethamster escaped. He searched in…

参考:https://blog.csdn.net/yuweiming70/article/details/79684433 题目描述: International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to ".-", "b" maps to &q…

International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to ".-", "b" maps to "-...", "c" maps to "-.-.", and so on. F…

International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to ".-", "b" maps to "-...", "c" maps to "-.-.", and so on. F…

International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to ".-", "b"maps to "-...", "c" maps to "-.-.", and so on. Fo…

Description International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to ".-", "b" maps to "-...", "c" maps to "-.-.",…

Algorithm [leetcode]Unique Morse Code Words https://leetcode.com/problems/unique-morse-code-words/ 1)problem International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to…

International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to ".-", "b" maps to "-...", "c"maps to "-.-.", and so on. Fo…

题目要求 International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to ".-", "b" maps to "-...", "c" maps to "-.-.", and so…

International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a"maps to ".-", "b" maps to "-...", "c" maps to "-.-.", and so on. Fo…

International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a"maps to ".-", "b" maps to "-...", "c" maps to "-.-.", and so on. Fo…

从周三课开始总算轻松了点,下午能在宿舍研究点题目啥的打一打,还好,刚开学的课程还算跟得上,刚开学的这些课程也是复习以前学过的知识,下半学期也不敢太划水了,被各种人寄予厚望之后瑟瑟发抖,只能努力前行了~自己好多地方还做得不够好,真的是要提升的方面太多了,加油吧~ 今日兴趣新闻: 网易回应裁员:公司确实正在进行结构性优化 链接:https://baijiahao.baidu.com/s?id=1626619207432301200&wfr=spider&for=pc 偶尔反新闻经常看到这些大公…

回溯法是一种选优搜索法(试探法),被称为通用的解题方法,这种方法适用于解一些组合数相当大的问题.通过剪枝(约束+限界)可以大幅减少解决问题的计算量(搜索量). 基本思想 将n元问题P的状态空间E表示成一棵高为n的带权有序树T,把在E中求问题P的解转化为在T中搜索问题P的解. 深度优先搜索(Depth-First-Search,DFS)是一种用于遍历或搜索树或图的算法.沿着树的深度遍历树的节点,尽可能深的搜索树的分支.当节点v的所在边都己被探寻过,搜索将回溯到发现节点v的那条边的起始节点.这一过程…

Unique Morse Code Words Description International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to ".-", "b" maps to "-...", "c" ma…

题目标签:String 题目给了我们 对应每一个 字母的 morse 密码,让我们从words 中 找出 有几个不同的 morse code 组合. 然后只要遍历 words,把每一个word 转换成 morse code,把 唯一的 存入 HashSet 就可以了,最后返回 set 的 size. Java Solution: Runtime beats  99.77% 完成日期:07/02/2018 关键词:HashSet 关键点:把唯一morse code 存入 set class Sol…

html水波纹样式,源码直接下载,代码有注释教程,小白可以看懂. 动画啥的都做好了,效果我觉得还不错 网上文章看到xbox 工程师使用隐写术,在界面的右下角放上了含有用户激活码的水波纹样式,一般人还真看不出来. 于是仿制了一个 先把莫尔兹转码部分放上来吧,莫尔兹转换部分是网上某位大佬写的,照抄. 完整代码下载在最后边 var utils = utils || {}; utils.isArray = function(value) { return Object.prototype.toStrin…

International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a"maps to ".-", "b" maps to "-...", "c" maps to "-.-.", and so on. Fo…

problem 804. Unique Morse Code Words solution1: class Solution { public: int uniqueMorseRepresentations(vector<string>& words) { vector<string> morse{".-", "-...","-.-.","-..",".","..-…

链接:https://ac.nowcoder.com/acm/contest/3665/E来源:牛客网 题目描述 Morse code is a character encoding scheme used in telecommunication that encodes text characters as standardized sequences of two different signal durations called dots and dashes or dits and d…

目录 一.关于DFS 1. 什么是DFS 2. DFS的搜索方式 二.DFS的具体实现 三.剪枝 1. 顺序性剪枝 2. 重复性剪枝 3. 可行性剪枝 4. 最优性剪枝 5. 记忆化剪枝 四.练习 一.关于DFS 1. 什么是DFS 深度优先搜索算法,又称DFS(Depth First Search).DFS算法是一种搜索算法,而搜索算法实质上是一种枚举,即借助计算机的高性能来有目的地枚举一个问题的部分情况或这个问题的所有情况,进而求出问题的解的一种方法. 2. DFS的搜索方式 根据算法的名字…

804. Unique Morse Code Words (Easy)# International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to ".-", "b" maps to "-...", "c" m…

Question 804. Unique Morse Code Words [".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-…

转载请注明出处:http://blog.csdn.net/u012860063?viewmode=contents 题目链接:http://poj.org/problem? id=2488 ----------------------------------------------------------------------------------------------------------------------------------------------------------…

DFS模板 void dfs(int depth)//depth表示当前的层数(或深度) { if(depth>n)//到达叶子节点,该路已走到尽头 return; for(int i=;i<=n;i++)//n表示最大的值,即最大深度为n { if(b[i]==)//b数组表示探索的状态,1表示已被探索,0表示尚未被探索 { b[i]=;//标记当前的b[i]已被探索 a[level]=i;//记录当前的节点值 dfs(level+);//进一步的搜索 b[i]=;//还原当前的b[i]元素…

Secret Code Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 670    Accepted Submission(s): 109 Problem Description The Sarcophagus itself is locked by a secret numerical code. When somebody wan…