//该程序需要连接数据库.根据word文档要求所有功能均已实现.//大部分方法基本差不多,//在查询修改的时候能输出 最大ID号 和最小ID号,并且可以对输入的ID号进行判断是否存在(具体方法请查看 修改电话号码, 其他修改方法暂时没有相对完善, 只针对修改电话号码的方法进行了修改,方便后期对编写程序思路的查看).package 电话薄1; public class Menu { //主菜单 public void mainMenu() { for(int i = 0 ; i >= 0 ; i…
第一题:输入字符串长度len1,字符串s1,字符串长度len2,字符串s2.从后向前比较,以最短字符串为标准,输出不同的元素的个数. 例如: 输入:s1="1,3,5" len1=3 s2="2,4,1,7,5" len2=5 输出:1 函数原型 public int getDiffNum(int len1, String s1, int len2, String s2) [java] : public class HuaWeiTest …
引用:Java Programming Language Enhancements Java Programming Language Enhancements Enhancements in Java SE 7 Binary Literals - In Java SE 7, the integral types (byte, short, int, and long) can also be expressed using the binary number system. To specif…
public interface Path extends Comparable<Path>, Iterable<Path>, Watchable 1. A Path represents a path that is hierarchical and composed of a sequence of directory and file name elements separated by a special separator or delimiter. 2. A root…
题目:evaluate-reverse-polish-notation 要求: Evaluate the value of an arithmetic expression in Reverse Polish Notation. Valid operators are+,-,*,/. Each operand may be an integer or another expression. Some examples: ["2", "1", "+"…