SGU196_Matrix Multiplication】的更多相关文章

给一个无向图,如果第i个点连接第j条边,那么mat[i][j]=1,否则mat[i][j]=0. 求mat的转置乘以本身得到的矩阵每个位置的和是多少? 理解矩阵的意义就比较好做了. mat[i][j]表示i点可以连接到j边,转置后相乘的意义是第i边和第j边有公共点. 这样,我们只需要统计每个点的度数,这样我们就知道有多少组这样有公共点的边了,也就是最终的答案了. 如果是mat乘以mat的转置,思考的方法也是一样的. 召唤代码君: #include <iostream> #include <…
A multiplication game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6028   Accepted: 3013 Description Stan and Ollie play the game of multiplication by multiplying an integer p by one of the numbers 2 to 9. Stan always starts with p =…
                             Matrix Multiplication Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 18173   Accepted: 3912 Description You are given three n × n matrices A, B and C. Does the equation A × B = C hold true? Input The first l…
Matrix multiplication Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Problem Description Given two matrices A and B of size n×n, find the product of them. bobo hates big integers. So you are only asked to find t…
Matrix multiplication Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 820    Accepted Submission(s): 328 Problem Description Given two matrices A and B of size n×n, find the product of them. b…
A typical implementation Booth's algorithm can be implemented by repeatedly adding (with ordinary unsigned binary addition) one of two predetermined values A and S to a product P, then performing a rightward arithmetic shift on P. Let m and r be the…
http://acm.hdu.edu.cn/showproblem.php?pid=4951 2014多校 第八题 1008 2014 Multi-University Training Contest 8 Multiplication table Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 438    Accepted Submi…
hdu4920 Matrix multiplication Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 568    Accepted Submission(s): 225 Problem Description Given two matrices A and B of size n×n, find the product o…
题目链接:http://poj.org/problem?id=1651 Description The multiplication puzzle is played with a row of cards, each containing a single positive integer. During the move player takes one card out of the row and scores the number of points equal to the prod…
题目传送门 /* 题意:加上适当的括号,改变计算顺序使得总的计算次数最少 矩阵连乘积问题,DP解决:状态转移方程: dp[i][j] = min (dp[i][k] + dp[k+1][j] + p[i-1] * p[k] * p[j]) (i<=k<j) s[i][j] 记录断开的地方(即加括号的位置),回溯法输出结果 */ #include <cstdio> #include <cstring> #include <string> #include &l…