题目标签:Array, Hash Table 题目给了我们一个string array A,让我们找到common characters. 建立一个26 size 的int common array,作为common characters 的出现次数. 然后遍历每一个 string, 都建立一个 int[26] 的 temp array,来数每个char 出现的次数,当完成了这个str 之后, 把这个temp array 更新到 common 里面去,这里要挑最小的值存入.当完成所有string…

python可重集合操作 class Solution(object): def commonChars(self, A): """ :type A: List[str] :rtype: List[str] """ if not A: return [] from collections import Counter ans=Counter(A[0]) for str in A: ans&=Counter(str) ans=list(an…

package y2019.Algorithm.array; import java.util.*; /** * @ProjectName: cutter-point * @Package: y2019.Algorithm.array * @ClassName: CommonChars * @Author: xiaof * @Description: 1002. Find Common Characters * Given an array A of strings made only from…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 字典 日期 题目地址:https://leetcode.com/problems/find-common-characters/ 题目描述 Given an array A of strings made only from lowercase letters, return a list of all characters that show up…

题目如下: Given an array A of strings made only from lowercase letters, return a list of all characters that show up in all strings within the list (including duplicates).  For example, if a character occurs 3 times in all strings but not 4 times, you ne…

Given an array A of strings made only from lowercase letters, return a list of all characters that show up in all strings within the list (including duplicates).  For example, if a character occurs 3 times in all strings but not 4 times, you need to…

参考:https://leetcode.com/problems/find-common-characters/discuss/247573/C%2B%2B-O(n)-or-O(1)-two-vectors 地址:https://leetcode.com/problems/find-common-characters/ vector初始化:vector<int> a(7,3) // 把a初始化为包含7个值为3的int char转化为string:string(1,ch) for (auto s…

Given an array A of strings made only from lowercase letters, return a list of all characters that show up in all strings within the list (including duplicates).  For example, if a character occurs 3 times in all strings but not 4 times, you need to…

目录 题目链接 注意点 解法 小结 题目链接 Find Common Characters - LeetCode 注意点 不能单纯的以字母出现的次数来判断是否是公共的字母 解法 解法一:将第一个字符串的每个字母逐个在其他字符串中查找,如果所有的字符串都含有就加入res.时间复杂度O(n^2),n是所有字符串的长度之和. class Solution { public: vector<string> commonChars(vector<string>& A) { vecto…

转自出处 Write a program that gives count of common characters presented in an array of strings..(or array of character arrays) For eg.. for the following input strings..  aghkafgklt  dfghako  qwemnaarkf  The output should be 3. because the characters a,…