CF797E. Array Queries】的更多相关文章

a is an array of n positive integers, all of which are not greater than n. You have to process q queries to this array. Each query is represented by two numbers p and k. Several operations are performed in each query; each operation changes p to p + …
1100 - Again Array Queries   PDF (English) Statistics Forum Time Limit: 3 second(s) Memory Limit: 32 MB Given an array with n integers, and you are given two indices i and j (i ≠ j) in the array. You have to find two integers in the range whose diffe…
E. Array Queries 题目链接:http://codeforces.com/problemset/problem/797/E time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output a is an array of n positive integers, all of which are not greater than…
题目链接:codeforces 797 E. Array Queries   题意:给你一个长度为n的数组a,和q个询问,每次询问为(p,k),相应的把p转换为p+a[p]+k,直到p > n为止,求每次询问要转换的次数. 题解:纯暴力会TLE,所以在k为根号100000范围内dp打表 dp[i][j]表示初始p为i, k为j,需要转换几次可以大于n. 状态转移方程:dp[i][j] = dp[i+a[i]+j] + 1 #include <cstdio> #include <al…
797E - Array Queries 思路: 分段处理: 当k小于根号n时记忆化搜索: 否则暴力: 来,上代码: #include <cmath> #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; #define maxn 100005 ],size; inline void in(int &am…
                                                                                                              1082 - Array Queries Time Limit: 3 second(s) Memory Limit: 64 MB Given an array with N elements, indexed from 1 to N. Now you will be given…
                                                                          1100 - Again Array Queries                                                                                                  ->   Link   <- 又是这种区间查询最值问题,题目意思是要使得这个区间的两个数的差值最小值,…
Description You are given an array a of size n, and q queries to it. There are queries of two types: 1 li ri — perform a cyclic shift of the segment [li, ri] to the right. That is, for every x such that li ≤ x < ri new value of ax + 1 becomes equal t…
You are given an array a of size n, and q queries to it. There are queries of two types: 1 li ri — perform a cyclic shift of the segment [li, ri] to the right. That is, for every x such that li ≤ x < ri new value of ax + 1 becomes equal to old value…
题目链接:http://www.lightoj.com/volume_showproblem.php?problem=1100 给你n个数,数的范围是1~1000,给你q个询问,每个询问问你l到r之间数的最小差是多少. 要是l到r的数字个数大于1000,必定会有两个数字重复,所以此时最小差就为0.要是小于等于1000就直接暴力即可. //#pragma comment(linker, "/STACK:102400000, 102400000") #include <algorit…