Dynamic Inversions Time Limit: 30000/15000MS (Java/Others) Memory Limit: 128000/64000KB (Java/Others) SubmitStatus Problem Description 给出N个数a[1],a[2] ... a[N],有M个操作,每个操作给出x,y两个数,你将a[x],a[y]交换,然后求交换后数组的逆序对个数.逆序对的意思是1 <= i < j <= N 且a[i] > a[j].…

Dynamic Rankings Time Limit: 10 Seconds      Memory Limit: 32768 KB The Company Dynamic Rankings has developed a new kind of computer that is no longer satisfied with the query like to simply find the k-th smallest number of the given N numbers. They…

题意:一个逆序对罚钱x元,现在给你交换的机会,每交换任意相邻两个数花钱y,问你最少付多少钱 思路:最近在补之前还没过的题,发现了这道多校的题.显然,交换相邻两个数逆序对必然会变化+1或者-1,那我们肯定是-1操作.那么显然问题就变成了求逆序对数*min(x,y).树状数组求逆序对数. 代码: #include<set> #include<map> #include<stack> #include<cmath> #include<queue> #i…

Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 9094  Solved: 3808[Submit][Status][Discuss] Description 给定一个含有n个数的序列a[1],a[2],a[3]……a[n],程序必须回答这样的询问:对于给定的i,j,k,在a[i],a[i+1 ],a[i+2]……a[j]中第k小的数是多少(1≤k≤j-i+1),并且,你可以改变一些a[i]的值,改变后,程序还能针对改 变后的a继续回答上面的问题.…

题目大意:略 洛谷传送门 这道题在洛谷上数据比较强 貌似这个题比较常见的写法是树状数组套主席树,动态修改 我写的是整体二分 一开始的序列全都视为插入 对于修改操作,把它拆分成插入和删除两个操作 像$CDQ$分治一样,用结构体记录操作的位置,修改的权值等 假设为需要处理的询问分配了一个答案$mid$ 查询区间第$K$小,我们只需要查询区间内权值为$[l,mid]$的数有几个 每次插入/删除,都看这次操作修改的权值是否$\in[l,mid]$ 如果是,说明这个它对答案有贡献,在它在原序列的位置上$+…

#include<iostream> #include<algorithm> #include<cstring> #include<cstdio> using namespace std; typedef long long ll; ; int a[N]; int ra[N]; int tr[N]; int n,x,y; int sz; int lowbit(int x) { return x&-x; } void add(int x,int c)…

The Company Dynamic Rankings has developed a new kind of computer that is no longer satisfied with the query like to simply find the k-th smallest number of the given N numbers. They have developed a more powerful system such that for N numbers a[1],…

Dynamic Rankings Time Limit: 10 Seconds      Memory Limit: 32768 KB The Company Dynamic Rankings has developed a new kind of computer that is no longer satisfied with the query like to simply find the k-th smallest number of the given N numbers. They…

The Company Dynamic Rankings has developed a new kind of computer that is no longer satisfied with the query like to simply find the k-th smallest number of the given N numbers. They have developed a more powerful system such that for N numbers a[1],…

1901: Zju2112 Dynamic Rankings Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 6321  Solved: 2628[Submit][Status][Discuss] Description 给定一个含有n个数的序列a[1],a[2],a[3]……a[n],程序必须回答这样的询问:对于给定的i,j,k,在a[i],a[i+1],a[i+2]……a[j]中第k小的数是多少(1≤k≤j-i+1),并且,你可以改变一些a[i…