Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example, If nums = [1,2,2], a soluti…

给定一个可能包含重复元素的整数数组 nums,返回该数组所有可能的子集(幂集). 说明:解集不能包含重复的子集. 示例: 输入: [1,2,2] 输出: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] class Solution { public: int len; vector<vector<int> > res; vector<vector<int> > subsetsWithDup(vector<int>&…

Subsets Given a set of distinct integers, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example, If S = [1,2,3], a solution is: [ [3], [1], [2], [1…

Subsets II Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a so…

题目: Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If nums = [1,2,2], a sol…

78. Subsets Given a set of distinct integers, nums, return all possible subsets. Note: The solution set must not contain duplicate subsets. For example, If nums = [,,], a solution is: [ [], [], [], [,,], [,], [,], [,], [] ] class Solution { public: v…

目录 题目链接 注意点 解法 小结 题目链接 Subsets II - LeetCode 注意点 有重复的数字 数组可能是无序的,要先排序 解法 解法一:递归,只需要在Subsets中递归写法的基础上多加一句if(find(ret.begin(),ret.end(),tmp) == ret.end()) ret.push_back(tmp);j即可,因为已经排序了,所以加进去的如果已经存在就说明是重复的. class Solution { public: typedef vector<int>…

Subsets II Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a so…

第一题是输入数组的数值不相同,第二题是输入数组的数值有相同的值,第二题在第一题的基础上需要过滤掉那些相同的数值. level代表的是需要进行选择的数值的位置. 78. Subsets 错误解法: class Solution { public: vector<vector<int>> subsets(vector<int>& nums) { vector<vector<int> > result; if(nums.empty()) ret…

1. Word Search Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cel…

Subsets II 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/subsets-ii/description/ Description Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). Note: The solution set must not contain du…

Leetcode之回溯法专题-90. 子集 II(Subsets II) 给定一个可能包含重复元素的整数数组 nums,返回该数组所有可能的子集(幂集). 说明:解集不能包含重复的子集. 示例: 输入: [1,2,2] 输出: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 分析:是78题的升级版,新增了一些限制条件,nums数组是会重复的,求子集. class Solution { List<List<Integer>> ans = new Arr…

Subsets II Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If nums = [1,2,2]…

Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. Example: Input: [1,2,2] Output: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 给定一个可能…

1. Given a set of distinct integers, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If nums = [1,2,3], a solution is: [ [3], [1], [2], [1…

Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If nums = [1,2,2], a solutio…

Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: The solution set must not contain duplicate subsets. For example,If nums = [1,2,2], a solution is: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 分析: 因为有重…

Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a solution is:…

Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a solution is:…

Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,2], a solution is:…

题目来源 https://leetcode.com/problems/subsets-ii/ Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate su…

题意: 给一个集合,有n个可能相同的元素,求出所有的子集(包括空集,但是不能重复). 思路: 看这个就差不多了.LEETCODE SUBSETS (DFS) class Solution { public: vector<vector<int>> subsets(vector<int>& nums) { sort(nums.begin(),nums.end()); DFS(,nums,tmp); ans.push_back(vector<int>()…

题目: Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If nums = [1,2,2], a sol…

原题地址 跟Subsets(参见这篇文章)类似. 但因为有重复元素,所以要考虑去重问题. 什么情况下会出现重复呢?比如S = {5, 5, 5},如果要选1个5,一共有C(3,1)=3种选法,即100, 010, 001,这三种情况在集合的角度看是重复的情况.如果要选2个5,共有C(3,2)=3种选法,即011, 101, 110,这三种情况在集合的角度上看也是重复的. 本质在于,如果要在重复出现的数字当中选择若干个,则只能保留一种取法,其他的都是重复.即,这些重复数字对应的二进制位当中,只能保…

题目 带重复元素的子集 给定一个可能具有重复数字的列表,返回其所有可能的子集 样例 如果 S = [1,2,2],一个可能的答案为: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 注意 子集中的每个元素都是非降序的 两个子集间的顺序是无关紧要的 解集中不能包含重复子集 挑战 你可以同时用递归与非递归的方式解决么? 解题 一个很简单的想法就是在上一题目中增加判断是否已经存在某个子集 class Solution: """ @param S: A…

Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If nums = [1,2,2], a solutio…

Question Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example, if nums = [1,2,2],…

一.Subsets Given a set of distinct integers, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If nums = [1,2,3], a solution is: [ [3], [1],…

深度优先搜索算法(depth first search),是一个典型的图论算法.所遵循的搜索策略是尽可能“深”地去搜索一个图. 算法思想是: 对于新发现的顶点v,如果它有以点v为起点的未探测的边,则沿此边继续探测下去.当顶点v的所有边都已被探寻结束,则回溯到到达点v的先辈节点.以相同方法一直回溯到源节点为止.如果图中还有未被发现的顶点,则选择其中一个作为源顶点,重复以上的过程.最后的结果是一些不相交的深度优先树. leetCode中的应用: Given a collection of integ…

给定一个数组,返回所有的非重复的可能.例如给定 If S = [1,2,2], a solution is: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 其实这题类似的有Combination和Subsets.有兴趣的可以看看之前的解题方法.那大概是第70题左右,十天以前做的吧.记得当时用了回溯法.现在这个还是要用到回溯.只是加了判断有重复的子集怎么办. 在回溯的过称中,记录一种可能后就把最后一个pop掉,然后回溯上一个的时候判断是不是和之前判断过的相等了.用…