Communication System Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 29218   Accepted: 10408 Description We have received an order from Pizoor Communications Inc. for a special communication system. The system consists of several devices…

A Bug's Life Time Limit: 10000MS   Memory Limit: 65536K Total Submissions: 38280   Accepted: 12452 Description Background Professor Hopper is researching the sexual behavior of a rare species of bugs. He assumes that they feature two different gender…

Description We have received an order from Pizoor Communications Inc. for a special communication system. The system consists of several devices. For each device, we are free to choose from several manufacturers. Same devices from two manufacturers d…

题意: 给出n个工厂的产品参数带宽b和价格p,在这n个工厂里分别选1件产品共n件,使B/P最小,其中B表示n件产品中最小的b值,P表示n件产品p值的和. 输入 iCase n 表示iCase个样例n个工厂 m1 p1 b1 p2 b2..pm1 bm1 //第一个工厂有m1个同种类不同参数的产品,每一个产品的参数分别是p1 b1 p2 b2 m2 p1 b1 p2 b2..pm2 bm2 ... mn p1 b1 p2 b2..pmn bmn 思路: 排序,先把b从小到大排序,然后把p从小到大排…

http://poj.org/problem?id=1018 题意: 某公司要建立一套通信系统,该通信系统需要n种设备,而每种设备分别可以有m1.m2.m3.....mn个厂家提供生产,而每个厂家生产的同种设备都会存在两个方面的差别:带宽bandwidths 和 价格prices. 现在每种设备都各需要1个,考虑到性价比问题,要求所挑选出来的n件设备,要使得B/P最大. 其中B为这n件设备的带宽的最小值,P为这n件设备的总价. 思路:DP解决. d[i][j]代表选择第i个设备时最小带宽j时的价…

看题传送门:http://poj.org/problem?id=1018 题目大意: 某公司要建立一套通信系统,该通信系统需要n种设备,而每种设备分别可以有m个厂家提供生产,而每个厂家生产的同种设备都会存在两个方面的差别:带宽bandwidths 和 价格prices. 现在每种设备都各需要1个,考虑到性价比问题,要求所挑选出来的n件设备,要使得B/P最大. 其中B为这n件设备的带宽的最小值,P为这n件设备的总价. 思路: 贪心+枚举 要使得B/P最大,则B应该尽量大,而P尽量小. 可以按照价格…

题目链接:http://poj.org/problem?id=1018 题目大意:有n种通讯设备,每种有mi个制造商,bi.pi分别是带宽和价格.在每种设备中选一个制造商让最小带宽B与总价格P的比值B/P最大. 解法是枚举最小带宽B,每种设备在带宽大于B的制造商中找价格最小的,最后取比值最大的. 详见代码: #include<cstdio> #include<cmath> #include<cstring> #include<algorithm> using…

点击打开链接 Communication System Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 21007   Accepted: 7449 Description We have received an order from Pizoor Communications Inc. for a special communication system. The system consists of several d…

Prime Distance Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 18731   Accepted: 5006 Description The branch of mathematics called number theory is about properties of numbers. One of the areas that has captured the interest of number th…

题意:给你n个厂,每个厂有m个产品,产品有B(带宽),P(价格),现在要你求最大的 B/P 明显是枚举,当P大于一定值,B/P为零,可以用这个剪枝 #include <iostream> #include<cstring> #include<cstdio> using namespace std; #define N 110 #define INF 0xffffff int devb[N][N],devp[N][N]; int b[N*100],tb; int main…

Communication System Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 21631   Accepted: 7689 Description We have received an order from Pizoor Communications Inc. for a special communication system. The system consists of several devices.…

Description We have received an order from Pizoor Communications Inc. for a special communication system. The system consists of several devices. For each device, we are free to choose from several manufacturers. Same devices from two manufacturers d…

We have received an order from Pizoor Communications Inc. for a special communication system. The system consists of several devices. For each device, we are free to choose from several manufacturers. Same devices from two manufacturers differ in the…

#include<iostream> #define MAXN 105 #define inf 10000000 #include<vector> #include<iomanip> #include<algorithm> using namespace std; struct node { double b; double p; }; vector<double> coll; node _m[MAXN][MAXN]; int size[MAXN…

Communication System Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 22380   Accepted: 7953 Description We have received an order from Pizoor Communications Inc. for a special communication system. The system consists of several devices.…

Communication System Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 25653   Accepted: 9147 Description We have received an order from Pizoor Communications Inc. for a special communication system. The system consists of several devices.…

本题一看似乎是递归回溯剪枝的方法.我一提交,结果超时. 然后又好像是使用DP,还可能我剪枝不够. 想了非常久,无奈忍不住偷看了下提示.发现方法真多.有贪心,DP,有高级剪枝的.还有三分法的.八仙过海各显神通啊. 坏习惯了,没思考够深入就偷看提示了. 幸好及时回头,还不须要看别人的代码了.自己做出来之后,有空看看多种解法的代码也好. 然后我想出自己的思路了,使用贪心,剪枝,DP综合优化下,呵呵.最后程序有点复杂.优化到了16ms,运气好点,或者vector换成原始数组的话,应该能够0MS了. 整体…

                                                                          通讯系统 We have received an order from Pizoor Communications Inc. for a special communication system. The system consists of several devices. For each device, we are free to choos…

A:水 #include <bits/stdc++.h> #include <cstring> #include <iostream> #include <algorithm> #define EPS 1.0e-8 #define PI acos(-1.0) #define INF 3000000000 #define MOD 1000000009 #define mem(a,b) memset((a),b,sizeof(a)) #define TS pri…

动态规划与贪心相关: {HDU}{4739}{Zhuge Liang's Mines}{压缩DP} 题意:给定20个点坐标,求最多有多少个不相交(点也不相交)的正方形 思路:背包问题,求出所有的正方形,然后求最多有多少个正方形不互相覆盖,这题真是神思路. {POJ}{3846}{Mountain Road} 题意:给定两个地点车的班次,路是双向单车道,求安排最短的时间 思路:对车次序列进行二维DP转移,转移的时候需要注意时刻的维护.这个题目的DP思路是正向DP,每次遍历到f[i][j]都需要更新…

Linear Regression The Normal Equation Computational Complexity 线性回归模型与MSE. the normal equation: a closed-form solution to find the value of θ that minimize the cost function. generate some linear-looking data to test this equation. inv() to compute t…

题目链接: http://poj.org/problem?id=2402 题目大意就是让你找到第n个回文数是什么. 第一个思路当然是一个一个地构造回文数直到找到第n个回文数为止(也许大部分人一开始都是这样的思路). 很明显找到第n个之前的所有操作都是浪费, 这也是这个方法的最大弱点. 抱着侥幸心理(谁知道数据弱不弱啊)用这种方法提交了下, TLE (在另一个OJ上提交是9个测试点过了6个). 第二个思路也很容易想到, 但是比第一个思路要麻烦: 第n个回文数的每位数字都与n有一定的关联. 也就是说…

[SinGuLaRiTy-1024] Copyright (c) SinGuLaRiTy 2017. All Rights Reserved. [POJ 2709] 颜料 (Painter) 题目描述 杂货店出售一种由N(3<=N<=12)种不同颜色的颜料,每种一瓶(50ML),组成的颜料套装.你现在需要使用这N种颜料:不但如此,你还需要一定数量的灰色颜料.杂货店从来不出售灰色颜料——也就是它不属于这N种之一.幸运的是,灰色颜料是比较好配置的,如果你取出三种不同颜色的颜料各x ml,混合起来就…

Contest 11.13 2016ACM/ICPC亚洲区青岛站(5/13, solved 7/13) Training 11.06 2016年中国大学生程序设计竞赛(合肥)(solved 6/10) 10.30 2016ACM/ICPC亚洲区沈阳站(solved 6/13) Todo CF 橙名 CF DIV2 (75/100) 读论文 模板横向排版 11.17 增加数学方面题目的练习. 精简模板. 11.06 线性规划.simplex 斯坦纳树 可持久化并查集 fwt 10.30 AtCod…

A POJ 1018 Communication System B POJ 1050 To the Max C POJ 1083 Moving Tables D POJ 1125 Stockbroker Grapevine E POJ 1143 Number Game F POJ 1157 LITTLE SHOP OF FLOWERS G POJ 1163 The Triangle H POJ 1178 Camelot I POJ 1179 Polygon J POJ 1189 钉子和小球 K…

If you find yourself needing to sit down to take off your shoes, it might be time to start paying attention to your sense of balance. People don't usually think about balance until they fall, but little signs such as relying on handrails to go up and…

2019年1月8日 1.Luogu P2147 [SDOI2008]洞穴勘测 (LCT模板题&LCT学习) 2019年1月9日 2.LuoguP3203 [HNOI2010]弹飞绵羊  (LCT模板题II&LCT进一步学习)   2019年1月10日 3.P3690 [模板]Link Cut Tree (动态树) 4.P2387 [NOI2014]魔法森林  (动态树维护最小生成树) 又颓了一个早上,这样下去布星啊,要被暴打啦 5.P2168 [NOI2015]荷马史诗 (哈夫曼树模板题)…

Pytorch中的BatchNorm的API主要有: 1 torch.nn.BatchNorm1d(num_features, 2 3 eps=1e-05, 4 5 momentum=0.1, 6 7 affine=True, 8 9 track_running_stats=True) 一般来说pytorch中的模型都是继承nn.Module类的,都有一个属性trainning指定是否是训练状态,训练状态与否将会影响到某些层的参数是否是固定的,比如BN层或者Dropout层.通常用model.t…

/*Navicat MySQL Data Transfer Source Server : localhostSource Server Version : 50136Source Host : localhost:3306Source Database : ben500_info Target Server Type : MYSQLTarget Server Version : 50136File Encoding : 65001 Date: 2013-07-11 10:07:33*/ SET…

2014 Multi-University Training Contest 9#11 Killing MonstersTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 562    Accepted Submission(s): 308 Problem Description Kingdom Rush is a popular TD…