[抄题]: You have a list of words and a pattern, and you want to know which words in words matches the pattern. A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 字典+set 单字典 日期 题目地址:https://leetcode.com/problems/find-and-replace-pattern/description/ 题目描述 You have a list of words and a pattern, and you want to know which words in words ma…
You have a list of words and a pattern, and you want to know which words in words matches the pattern. A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get the d…
You have a list of words and a pattern, and you want to know which words in words matches the pattern. A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get the d…
把pattern映射到数字,也就是把pattern标准化. 比如abb和cdd如果都能标准化为011,那么就是同构的. class Solution: def findAndReplacePattern(self, words: List[str], pattern: str) -> List[str]: p = self.get_pattern(pattern) ans = [] for w in words: if self.get_pattern(w) == p: ans.append(w…
题目:给定一个字符串S(主串),一个字符串数组words,其中的字符串的长度相同.找到所有的子串位置,要求是words中字符串的一个连接: 举例: For example, given:s: "barfoothefoobarman"words: ["foo", "bar"] You should return the indices: [0,9]. 解题思路: 1. 采用窗口机制,假设此时每个单词的长度为wordlen; 2. 先将words…