1004 Counting Leaves (30分)】的更多相关文章

1004 Counting Leaves (30分) A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Specification: Each input file contains one test case. Each case starts with a line containing 0…
1004 Counting Leaves (30分)   A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Specification: Each input file contains one test case. Each case starts with a line containing…
题意:给出一棵树的点数N,输入M行,每行输入父亲节点An,儿子个数n,和a1,a2,...,an(儿子结点编号),从根节点层级向下依次输出当前层级叶子结点个数,用空格隔开.(0<N<100) AAAAAccepted code: #include<bits/stdc++.h> using namespace std; vector<]; queue<int>q; ; ; ; ; ; void BFS(){ int x=q.front();//队头元素调用 if(v…
A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Specification: Each input file contains one test case. Each case starts with a line containing 0, the number of nodes in a…
1004 Counting Leaves (30)(30 分) A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Each input file contains one test case. Each case starts with a line containing 0 < N < 10…
1004. Counting Leaves (30)   A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Each input file contains one test case. Each case starts with a line containing 0 < N < 100,…
1004. Counting Leaves (30) A family hierarchy is usually presented by a pedigree tree. Your job is to count those family members who have no child. Input Each input file contains one test case. Each case starts with a line containing 0 < N < 100, th…
A family hierarchy is usually presented by a pedigree tree.  Your job is to count those family members who have no child. Input Each input file contains one test case. Each case starts with a line containing 0 < N < 100, the number of nodes in a tre…
题目链接:https://www.patest.cn/contests/pat-a-practise/1004 大意:输出按层次输出每层无孩子结点的个数 思路:vector存储结点,dfs遍历 #include<iostream> #include<cstdio> #include<string> #include<vector> #include<algorithm> using namespace std; ; int n,m,k,x,f[m…
利用广度优先搜索,找出每层的叶子节点的个数. #include <iostream> #include <vector> #include <queue> #include <fstream> using namespace std; vector<vector<int>> tree; vector<int> ans; void BFS(int s) { queue<pair<int, int>>…