题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/678 5-16 Sort with Swap(0, i)   (25分) Given any permutation of the numbers {0, 1, 2,..., N-1N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is…

1067 Sort with Swap(0, i) (25 分)   Given any permutation of the numbers {0, 1, 2,..., N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may…

Given any permutation of the numbers {0, 1, 2,..., N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may apply the swap operations in the fo…

Given any permutation of the numbers {0, 1, 2,..., N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may apply the swap operations in the fo…

Given any permutation of the numbers {0, 1, 2,..., N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may apply the swap operations in the fo…

一.技术总结 题目要求是,只能使用0,进行交换位置,然后达到按序排列,所使用的最少交换次数 输入时,用数组记录好每个数字所在的位置. 然后使用for循环,查看i当前位置是否为该数字,核心是等待0回到自己的位置上,如果没有一直与其他的数字进行交换.如果这个过程中,i回到自己位置上就不用调换,如果不是那么直接与0位置进行调换,直到所有位置都到指定位置上面. 二.参考代码 #include<iostream> #include<algorithm> using namespace std…

题意: 输入一个正整数N(<=100000),接着输入N个正整数(0~N-1的排列).每次操作可以将0和另一个数的位置进行交换,输出最少操作次数使得排列为升序. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ],b[]; int main(){ ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(…

Given any permutation of the numbers {0, 1, 2,..., N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may apply the swap operations in the fo…

题目链接:1067 Sort with Swap(0, i) (25 分) 题意 给定长度为 \(n\) 的排列,如果每次只能把某个数和第 \(0\) 个数交换,那么要使排列是升序的最少需要交换几次. 思路 贪心 由于是排列,所以排序后第 \(i\) 个位置上的数就是 \(i\).所以当 \(a[0] \neq 0\) 时,把 \(a[0]\) 位置上的元素交换到相应位置.如果 \(a[0] = 0\),就找到第一个不在正确位置上的数,把它与第 \(0\) 个数交换,那么下一次又是第一种情况了,…

Source: PAT A1067 Sort with Swap(0, i) (25 分) Description: Given any permutation of the numbers {0, 1, 2,..., N−1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort…