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Exam time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output An exam for n students will take place in a long and narrow room, so the students will sit in a line in some order. The teacher suspects…
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2019 杭电多校 7 1006 题目链接:HDU 6651 比赛链接:2019 Multi-University Training Contest 7 Problem Description Final Exam is coming! Cuber QQ has now one night to prepare for tomorrow's exam. The exam will be a exam of problems sharing altogether \(m\) points. Cub…
An exam for n students will take place in a long and narrow room, so the students will sit in a line in some order. The teacher suspects that students with adjacent numbers (i and i + 1) always studied side by side and became friends and if they take…
题目: 1026: 丑数 Time Limit: 1000 MS Memory Limit: 65536 KB Total Submit: 257 Accepted: 112 Page View: 1467 Submit Status Discuss Description 丑数就是这个数的质因子只有2,3,5,7这四个,除此之外不再含有其它 别的质因子. 注意1也被认为是丑数.丑数的前20个为 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 14, 15, 16, 18,…
time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Mishka is trying really hard to avoid being kicked out of the university. In particular, he was doing absolutely nothing for the whole semes…
思路如下: 1.输入n>>a>>b; 2.用一个循环缩小范围求出a,b所示的数所在的圈数q; 3.再一个循环求出圈数q的第1个数的值sum; 4.用四个if判断a,b所示的数在本圈q的上或下或左或右; 5.根据位置求出t(在sum的基础上需要+的值) 6.输出<<sum+t; 代码如下: #include <iostream> using namespace std; int main(int argc, char *argv[]) { int n,a,b,…
1.cos趋近 // a reasonable approximation of cosine interpolation double smoothStepInterp( double t ) { return (t*t)*(3.0-2.0*t); } 2.pow趋近 // rough approximation of pow(x,y) double powFast( double x, double y ) { return x/(x+y-y*x); } 3. // accel/decel…
C. Maximum splitting time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given several queries. In the i-th query you are given a single positive integer ni. You are to represent ni as…