题目链接 比赛时随便找了个规律,然后队友过了.不过那个规律具体细节还挺烦的.刚刚偶然看到Q巨在群里提到的他的一个思路,妙啊,很好理解,而且公式写起来也容易.OrzQ巨 #include<bits/stdc++.h> using namespace std; typedef long long LL; LL n,m; int main() { while(~scanf("%lld%lld",&n,&m)) { n--,m--; LL g=__gcd(n,m);…
A Simple Problem with Integers 这个题目首先要打表找规律,这个对2018取模最后都会进入一个循环节,这个循环节的打表要用到龟兔赛跑. 龟兔赛跑算法 floyed判环算法 这个算法我觉得还是很有意思的,可以学习一下. 不过这个题目这个算法打表还是有点难写的. 由这个算法可以得到这个循环节的最大长度是6 最大入环距离是4. 为什么有些循环节不是6,还是可以用6呢,因为每个元素平方最大周期为6,且6是其他所有周期的公倍数. 然后学完之后还是不太会这个题目怎么写,2018…
题目链接 Problem Description KazaQ wears socks everyday. At the beginning, he has n pairs of socks numbered from 1 to n in his closets. Every morning, he puts on a pair of socks which has the smallest number in the closets. Every evening, he puts this pa…
Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). Input The input consists of multiple test cases. Each test case co…
B. Position in Fraction time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You have a fraction . You need to find the first occurrence of digit c into decimal notation of the fraction after de…
Cyclic Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 193 Accepted Submission(s): 125 Problem Description Count the number of cyclic permutations of length n with no continuous subsequence…