Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. Example 1: Input: n = 12 Output: 3 Explanation: 12 = 4 + 4 + 4. Example 2: Input: n = 13 Output: 2 Explanation: 13 = 4 + 9. dp…

Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. Example 1: Input: n = 12 Output: 3 Explanation: 12 = 4 + 4 + 4. Example 2: Input: n = 13 Output: 2 Explanation: 13 = 4 + 9. Cr…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 四平方和定理 动态规划 日期 题目地址:https://leetcode.com/problems/perfect-squares/ 题目描述 Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, -…

Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. For example, given n = 12, return 3 because 12 = 4 + 4 + 4; given n = 13, return 2 because 13 = 4 + 9. 代码如下: public class Solu…

https://leetcode.com/problems/perfect-squares/ Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. For example, given n = 12, return 3 because 12 = 4 + 4 + 4; given n = 13, retur…

Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. Example 1: Input: n = 12 Output: 3 Explanation: 12 = 4 + 4 + 4. Example 2: Input: n = 13 Output: 2 Explanation: 13 = 4 + 9.---…

给定正整数 n,找到若干个完全平方数(比如 1, 4, 9, 16, ...) 使得他们的和等于 n.你需要让平方数的个数最少.比如 n = 12,返回 3 ,因为 12 = 4 + 4 + 4 : 给定 n = 13,返回 2 ,因为 13 = 4 + 9. 详见:https://leetcode.com/problems/perfect-squares/description/ Java实现: 方法一:递归实现 class Solution { public int numSquares(i…

原题链接 题意: 给一个非整数,算出其最少可以由几个完全平方数组成(1,4,9,16……) 思路: 可以得到一个状态转移方程  dp[i] = min(dp[i], dp[i - j * j] + ); 代码如下: Runtime: 60 ms, faster than 69.83% 有点慢 class Solution { public: int numSquares(int n) { ]; ; i <= n; i++) { dp[i] = i; ; j * j <= i; j++) { d…

要求 给出一个正整数n,寻找最少的完全平方数,使他们的和为n 示例 n = 12 12 = 4 + 4 + 4 输出:3 边界 是否可能无解 思路 贪心:12=9+1+1+1,无法得到最优解 图论:从n到0,每个数字表示一个节点,如果两个数字x到y相差一个完全平方数,则连接一条边 问题转化为无权图中从n到0的最短路径    实现 队列中每个元素是一个pair对,保存具体数字和经历了几段路径走到这个数字 1 class Solution { 2 public: 3 int numSquares(i…

279. 完全平方数 279. Perfect Squares 题目描述 给定正整数 n,找到若干个完全平方数(比如 1, 4, 9, 16, ...)使得它们的和等于 n.你需要让组成和的完全平方数的个数最少. 每日一算法2019/5/10Day 7LeetCode279. Perfect Squares 示例 1: 输入: n = 12 输出: 3 解释: 12 = 4 + 4 + 4. 示例 2: 输入: n = 13 输出: 2 解释: 13 = 4 + 9. Java 实现 略 参考资…

LeetCode 279. Perfect Squres DP 是笨办法中的高效办法,又是一道可以被好办法打败的 DP 题. 题目描述 Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. Example 1: Input: n = 12 Output: 3 Explanation: 12 = 4 + 4…

Leetcode之广度优先搜索(BFS)专题-279. 完全平方数(Perfect Squares) BFS入门详解:Leetcode之广度优先搜索(BFS)专题-429. N叉树的层序遍历(N-ary Tree Level Order Traversal) 给定正整数 n,找到若干个完全平方数(比如 1, 4, 9, 16, ...)使得它们的和等于 n.你需要让组成和的完全平方数的个数最少. 示例 1: 输入: n = 12 输出: 3 解释: 12 = 4 + 4 + 4. 示例 2: 输…

原文地址 https://www.jianshu.com/p/2925f4d7511b 迫于就业的压力,不得不先放下 iOS 开发的学习,开始走上漫漫刷题路. 今天我想聊聊 LeetCode 上的第279题-Perfect Squares,花了挺长时间的,试了很多方法,作为一个算法新手,个人感觉这题很好,对我的水平提升很有帮助.我在这里和大家分享一下我的想法.下面是题目: Given a positive integer n, find the least number of perfect s…

题目 Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. 给定正整数 n,找到若干个完全平方数(比如 1, 4, 9, 16, ...)使得它们的和等于 n.你需要让组成和的完全平方数的个数最少. Example 1: Input: n = 12 Output: 3 Explanation: 12 =…

Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. ExampleGiven n = 12, return 3 because 12 = 4 + 4 + 4Given n = 13, return 2 because 13 = 4 + 9 LeetCode上的原题,请参见我之前的博客Perfect Sq…

原题链接在这里:https://leetcode.com/problems/perfect-squares/ 题目: Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. For example, given n = 12, return 3 because 12 = 4 + 4 + 4; given n…

Perfect Squares Total Accepted: 18854 Total Submissions: 63048 Difficulty: Medium Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. For example, given n = 12, return 3 because …

CF914A Perfect Squares 题意翻译 给定一组有n个整数的数组a1,a2,…,an.找出这组数中的最大非完全平方数. 完全平方数是指有这样的一个数x,存在整数y,使得x=y^2y2 . 输入格式 第一行输入一个单独的整数n(1<=n<=1000 ),n为该组数的数量. 接下来有n个整数,a1,a2,an(-10^6<=a<=10^6) 数据保证至少存在一个整数是非完全平方数. 题目描述 Given an array a_{1},a_{2},...,a_{n}a1​…

题目来源:Light OJ 1288 Subsets Forming Perfect Squares 题意:给你n个数 选出一些数 他们的乘积是全然平方数 求有多少种方案 思路:每一个数分解因子 每隔数能够选也能够不选 0 1表示 然后设有m种素数因子 选出的数组成的各个因子的数量必须是偶数 组成一个m行和n列的矩阵 每一行代表每一种因子的系数 解出自由元的数量 #include <cstdio> #include <cstring> #include <algorithm&…

Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16 ...) which sum to n. For example, given n = 12, return 3 because 12 = 4 + 4 + 4; given n = 13, return 2 because 13 = 4 + 9. 解析: 利用动态规划解决此问题:对于要求的当前节…

题目 Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, -) which sum to n. For example, given n = 12, return 3 because 12 = 4 + 4 + 4; given n = 13, return 2 because 13 = 4 + 9. 分析 完美平方数,给定任意数n,它可表示为多…

题目描述 给定正整数 n,找到若干个完全平方数(比如 1, 4, 9, 16, ...)使得它们的和等于 n.你需要让组成和的完全平方数的个数最少. 示例 1: 输入: n = 12 输出: 3 解释: 12 = 4 + 4 + 4. 示例 2: 输入: n = 13 输出: 2 解释: 13 = 4 + 9. 解题思路 利用动态规划思想解题,初始化dp数组令小于n的完全平方数为1,从1到n遍历求解最小组成个数,再对每个数遍历小于其的所有完全平方数,最小组成个数的状态转移方程为: dp[i] =…

Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. For example, given n = 12, return 3 because 12 = 4 + 4 + 4; given n = 13, return 2 because 13 = 4 + 9. Credits:Special thanks…

Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. For example, given n = 12, return 3 because 12 = 4 + 4 + 4; given n = 13, return 2 because 13 = 4 + 9. 题目如上,实际上相当于一个常规的背包问题,关于…

Given a positive integer n, find the least number of perfect square numbers (for example,1, 4, 9, 16, ...) which sum to n. Given n = 12, return 3 because 12 = 4 + 4 + 4Given n = 13, return 2 because 13 = 4 + 9 刷这道题目发现网上有四种解法 http://www.cnblogs.com/gr…

Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. For example, given n = 12, return 3 because 12 = 4 + 4 + 4; given n = 13, return 2 because 13 = 4 + 9. 题目大意:给一个正整数,找出可以由最少个平方数…

Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. Example 1: Input: n = 12 Output: 3 Explanation: 12 = 4 + 4 + 4. Example 2: Input: n = 13 Output: 2 Explanation: 13 = 4 + 9. 给定…

Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. Example 1: Input: n = 12 Output: 3 Explanation: 12 = 4 + 4 + 4. Example 2: Input: n = 13 Output: 2 Explanation: 13 = 4 + 9. 解题…

一原题 Given a positive integer n, find the least number of perfect square numbers (, , , , ...) which sum to n. For example, given n = , because = + + ; given n = , because = + . 二.中文讲解 .这道题说是给我们一个正整数,求它最少能由几个完全平方数组成.这道题是考察四平方和定理 .根据四平方和定理,任意一个正整数均可表示为…

题目描述: 给定正整数 n,找到若干个完全平方数(比如 1, 4, 9, 16, ...)使得它们的和等于 n.你需要让组成和的完全平方数的个数最少. 示例 1: 输入: n = 12 输出: 3 解释: 12 = 4 + 4 + 4. 示例 2: 输入: n = 13 输出: 2 解释: 13 = 4 + 9. 思路分析:思路: 动态规划首先初始化长度为n+1的数组dp,每个位置都为0如果n为0,则结果为0对数组进行遍历,下标为i,每次都将当前数字先更新为最大的结果,即dp[i]=i,比如i=…