https://leetcode.com/problems/find-all-duplicates-in-an-array/description/ 参考:http://www.cnblogs.com/grandyang/p/4843654.html Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all th…

题目描述 给定一个整数数组 a,其中1 ≤ a[i] ≤ n (n为数组长度), 其中有些元素出现两次而其他元素出现一次. 找到所有出现两次的元素. 你可以不用到任何额外空间并在O(n)时间复杂度内解决这个问题吗? 示例: 输入: [4,3,2,7,8,2,3,1] 输出: [2,3] 思路 思路一: 直接利用hashmap记录出现次数 思路二: 因为数组输入的特点 1<=a[i]<=n,则可以把原数组当hash表用 ,因为原数组是正数,标为负数表示出现过,如果遇到负数就表示第二次出现,就可以…

Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime? Example: Input: [4,3,2,7,…

题目 题目链接 Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime? Example: Input: […

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example,Given input array A = […

Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.…

后面3个题都是限制在1-n的,所有可以不先排序,可以利用巧方法做.最后两个题几乎一模一样. 217. Contains Duplicate class Solution { public: bool containsDuplicate(vector<int>& nums) { int length = nums.size(); ) return false; sort(nums.begin(),nums.end()); ;i < length;i++){ ]) return tr…

Question 442. Find All Duplicates in an Array Solution 题目大意:在数据中找重复两次的数 思路:数组排序,前一个与后一个相同的即为要找的数 Java实现: public List<Integer> findDuplicates(int[] nums) { List<Integer> ans = new ArrayList<>(); if (nums.length == 0) return ans; Arrays.so…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Follow up for "Remove Duplicates": What if duplicates are allowed at most twice? For example, Given sorted array nums = [1,1,1,2,2,3], Your function sho…

乘风破浪:LeetCode真题_026_Remove Duplicates from Sorted Array 一.前言     我们这次的实验是去除重复的有序数组元素,有大体两种算法. 二.Remove Duplicates from Sorted Array 2.1 问题      题目大意理解,就是对数组进行元素去重,然后返回去处重复之后的长度,无论我们对数组做了什么的修改,都没有关系的,只要保证再返回的长度之内的数组正确性即可.因为最后是根据长度来遍历的,因此我们不用担心. 2.2 分析…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 字典 原地变负 日期 题目地址:https://leetcode.com/problems/find-all-duplicates-in-an-array/description/ 题目描述 Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appe…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 26: Remove Duplicates from Sorted Arrayhttps://oj.leetcode.com/problems/remove-duplicates-from-sorted-array/ Given a sorted array, remove the duplicates in place such that each element appe…

https://leetcode.com/problems/remove-duplicates-from-sorted-array/ Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 双指针 日期 [LeetCode] https://leetcode.com/problems/remove-duplicates-from-sorted-array/ Total Accepted: 129010 Total Submissions: 384622 Difficulty: Easy 题目描述 Given a sorted array…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/remove-duplicates-from-sorted-array-ii/description/ 题目描述 Given a sorted array nums, remove the duplicates in-place such that duplicates ap…

Remove Duplicates from Sorted Array Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory.…

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example,Given input array nums …

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example,Given input array nums …

Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.…

Remove Duplicates from Sorted Array II Follow up for "Remove Duplicates":What if duplicates are allowed at most twice? For example,Given sorted array A = [1,1,1,2,2,3], Your function should return length = 5, and A is now [1,1,2,2,3]. 解法一: 我是Pic…

题目: Follow up for "Remove Duplicates":What if duplicates are allowed at most twice? For example,Given sorted array nums = [1,1,1,2,2,3], Your function should return length = 5, with the first five elements of nums being 1, 1, 2, 2 and 3. It does…

26.Remove Duplicates from Sorted Array Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input…

@requires_authorization @author johnsondu @create_time 2015.7.22 18:58 @url [remove dublicates from sorted array](https://leetcode.com/problems/remove-duplicates-from-sorted-array/) /** * @description: 从有序数组中剔除元素,最多常量额外空间,设置标兵依次比較 * @time_complexity:…

一.题目描写叙述 二.解题技巧 这道题和Remove Duplicates from Sorted Array这道题是相似的.仅仅只是这里同意出现反复的数字而已,能够採用二分搜索的变种算法.仅仅只是增加了剔除和第一个元素同样的元素的过程. 还有一个思路是增加一个变量.用于记录元素出现的次数.这题由于是已经排序的数组,所以一个变量就可以解决.假设是没有排序的数组,则须要引入一个hash表来记录出现次数. 三.演示样例代码 #include <iostream> #include <vect…

这是悦乐书的第149次更新,第151篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第8题(顺位题号是26).给定一个已经排序(由小到大)的整数数组(元素可以重复),计算其中不重复元素的个数n,并将数组的前n个元素依次赋值为筛选后的不重复元素.不许使用新数组接收数据.例如: nums = {1,1,2} 输出不重复元素的个数为2 数组前2个元素为1和2,即nums = {1,2,2} 本次解题使用的开发工具是eclipse,jdk使用的版本是1.8,环境是win7 6…

O(n)的算法就不说了,这题主要考查的是 O(logn)的算法. 有序数组easy想到使用二分查找解决.这题就是在二分基础上做一些调整.数组仅仅有一次翻转,能够知道原有序递增数组被分成两部分,这俩部分都是有序递增的(这题仅仅须要考虑有序数组的递增情况). 假如翻转后的数组以第 x 个结点分为两部分 A[0..x] 和 A[x+1..n].则 A[0..x] 这一段是有序递增的, A[x+1..n] 这一段也是有序递增的. 而且由于原数组是有序递增的,A[0..x] 中全部数都会大于 A[x+1.…

这是悦乐书的第365次更新,第393篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第227题(顺位题号是961).在大小为2N的数组A中,存在N+1个唯一元素,并且这些元素中的一个重复N次. 返回重复N次的元素.例如: 输入:[1,2,3,3] 输出:3 输入:[2,1,2,5,3,2] 输出:2 输入:[5,1,5,2,5,3,5,4] 输出:5 注意: 4 <= A.length <= 10000 0 <= A [i] <10000 A.lengt…

题目描述 26. 删除排序数组中的重复项 给定一个排序数组,你需要在原地删除重复出现的元素,使得每个元素只出现一次,返回移除后数组的新长度. 不要使用额外的数组空间,你必须在原地修改输入数组并在使用 O(1) 额外空间的条件下完成. 示例 1: 给定数组 nums = [1,1,2], 函数应该返回新的长度 2, 并且原数组 nums 的前两个元素被修改为 1, 2. 你不需要考虑数组中超出新长度后面的元素. 示例 2: 给定 nums = [0,0,1,1,1,2,2,3,3,4], 函数应该…

一天一道LeetCode系列 (一)题目 Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example, G…

题目 Follow up for "Remove Duplicates": What if duplicates are allowed at most twice? For example, Given sorted array nums = [1,1,1,2,2,3], Your function should return length = 5, with the first five elements of nums being 1, 1, 2, 2 and 3. It doe…