比赛时会错题意+不知道怎么线段树维护分数- - 思路来自题解 /* HDU 6070 - Dirt Ratio [ 二分,线段树 ] | 2017 Multi-University Training Contest 4 题意: 给出 a[N]; 设 size(l,r)为区间(l,r)不同数字的个数,求 size(l,r)/(r-l+1) 的最小值 限制: N <= 6e5, a[i] <= 6e5 分析: 二分答案 mid 则判定条件为是否存在 size(l,r)/(r-l+1) <=…

Dirt Ratio Time Limit: 18000/9000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Special Judge Problem Description In ACM/ICPC contest, the ''Dirt Ratio'' of a team is calculated in the following way. First let's ignore all the proble…

题目链接 Problem Description In ACM/ICPC contest, the ''Dirt Ratio'' of a team is calculated in the following way. First let's ignore all the problems the team didn't pass, assume the team passed X problems during the contest, and submitted Y times for t…

Dirt Ratio Time Limit: 18000/9000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 1473    Accepted Submission(s): 683Special Judge Problem Description In ACM/ICPC contest, the ''Dirt Ratio'' of a team is calculated…

http://acm.hdu.edu.cn/showproblem.php?pid=6070 题意: 找出一个区间,使得(区间内不同数的个数/区间长度)的值最小,并输出该值. 思路: 因为是要求$\frac{f(x)}{g(x)}$的最值,所以这是分数规划的题目,对于分数规划,是要用二分查找的方式去解决的. 就像官方题解说的,二分查找mid,二分答案mid,检验是否存在一个区间满足$\frac{size(l,r)}{(r-l+1)}<=mid$,表示l~r内不同数的个数. 先把上面的式子转化一下…

题 OvO http://acm.hdu.edu.cn/showproblem.php?pid=6070 (2017 Multi-University Training Contest - Team 4 - 1004) 解 二分答案 check时,要满足distinct(l,r)/(r-l+1)<val ,将这个不等式转化为distinct(l,r)+val*l<val*(r+1) check的时候,从左到右枚举右端点r,用线段树维护查询从1到r中选一个l,distinct(l,r)+val*…

地址:http://acm.split.hdu.edu.cn/showproblem.php?pid=6070 题面: Dirt Ratio Time Limit: 18000/9000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 1599    Accepted Submission(s): 740Special Judge Problem Description In…

/** 题目:hdu6070 Dirt Ratio 链接:http://acm.hdu.edu.cn/showproblem.php?pid=6070 题意:给定n个数,求1.0*x/y最小是多少.x表示一段区间内不同数字的个数,y表示区间长度. 思路:二分+线段树 二分答案x/y. 找一段区间满足 size(l,r)/(r-l+1) <= mid , size(l,r)表示[l,r]内不同数的个数. size(l,r)<=mid(r-l+1) => size(l,r)+mid*l<…

Dirt Ratio Time Limit: 18000/9000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 335    Accepted Submission(s): 105Special Judge Problem Description In ACM/ICPC contest, the ''Dirt Ratio'' of a team is calculated…

多校4 Dirt Ratio(二分+线段树) 题意: 给出n个数,找一段区间使得区间内不同数字个数除以区间长度最小,求这个最小值,\(n<=60000,a_i<=n\) 题解: 二分答案mid,检验是否存在一个区间满足\(\frac{size(l,r)}{r-l+1}\leq mid ​\),也就是\(size(l,r)+mid\times l\leq mid\times (r+1)\) 从左往右枚举每个位置作\(r\),当rr变化为\(r+1\)时,对\(size\)的影响是一段区间加1,线…