弹性碰撞 poj 3684】的更多相关文章

Simon is doing a physics experiment with N identical balls with the same radius of R centimeters. Before the experiment, all N balls are fastened within a vertical tube one by one and the lowest point of the lowest ball is H meters above the ground.…
Physics Experiment Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 2936   Accepted: 1045   Special Judge Description Simon is doing a physics experiment with N identical balls with the same radius of R centimeters. Before the experiment,…
Physics Experiment Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 1489   Accepted: 509   Special Judge Description Simon is doing a physics experiment with N identical balls with the same radius of R centimeters. Before the experiment,…
Physics Experiment Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 784   Accepted: 266   Special Judge Description Simon is doing a physics experiment with N identical balls with the same radius of R centimeters. Before the experiment, a…
原题如下: Physics Experiment Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 3583   Accepted: 1275   Special Judge Description Simon is doing a physics experiment with N identical balls with the same radius of R centimeters. Before the exper…
Description Simon ), the first ball is released and falls down due to the gravity. After that, the balls are released one by one in every second until all balls have been released. When a ball hits the ground, it will bounce back with the same speed…
强连通算法推断是否满足2-sat,然后反向建图,拓扑排序+染色. 一种选择是从 起点開始,还有一种是终点-持续时间那个点 開始. 若2个婚礼的某2种时间线段相交,则有矛盾,建边. easy出错的地方就在于推断线段相交. 若s1<e2&&s2<e1则相交 输出路径的做法能够參考论文2-SAT解法浅析 #include <iostream> #include<cstring> #include<cstdio> #include<string…
和蚂蚁问题类似. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<queue> #include<algorithm> using namespace std; int c,n; double h,r,t,T; ]; double cal(double time) { ) return h; ; ) { if(time<=T…
POJ 1852 Ants POJ 2386 Lake Counting POJ 1979 Red and Black AOJ 0118 Property Distribution AOJ 0333 Ball POJ 3009 Curling 2.0 AOJ 0558 Cheese POJ 3669 Meteor Shower AOJ 0121 Seven Puzzle POJ 2718 Smallest Difference POJ 3187 Backward Digit Sums POJ 3…
poj 1852 3684 这两题思路相似就放在一起. 1852 题意 一块长为L长度单位的板子(从0开始)上有很多只蚂蚁,给出它们的位置,它们的方向不确定,速度为每秒一长度单位,当两只蚂蚁相遇的时候,它们会反向而行,问所有蚂蚁到达终点(到0或者到L)所需要的最短时间和最长时间. 解析 一开始拿到这题觉得还是有点难度的,但一想通就发现这是个大水题.我们可以假设两只蚂蚁它们相向而行,并且它们中间没有别的蚂蚁,此时它们距离为k,经过时间t后它们相遇,此时它们反向,又经过时间t它们再次之间距离还是k.…