题目网址:http://poj.org/problem?id=3295 题目: Tautology Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 13231   Accepted: 5050 Description WFF 'N PROOF is a logic game played with dice. Each die has six faces representing some subset of the po…

题目:http://poj.org/problem?id=3295 题意:p,q,r,s,t,是五个二进制数. K,A,N,C,E,是五个运算符. K:&& A:||N:! C:(!w)||x E:w==x 题意是让求如果对于五个数的所有情况一个式子总是恒为1,那么这个式子就是tautology.输出tautology. 否则输出not. 5个数,最多有2^5种情况. 判断式子是不是恒为1,只需要从后往前判断即可. 这题好长时间没看懂,代码也是看网上大神的 #include<iost…

Tautology Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9580   Accepted: 3640 Description WFF 'N PROOF is a logic game played with dice. Each die has six faces representing some subset of the possible symbols K, A, N, C, E, p, q, r, s,…

Tautology Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9302   Accepted: 3549 Description WFF 'N PROOF is a logic game played with dice. Each die has six faces representing some subset of the possible symbols K, A, N, C, E, p, q, r, s,…

Tautology Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 7716   Accepted: 2935 Description WFF 'N PROOF is a logic game played with dice. Each die has six faces representing some subset of the possible symbols K, A, N, C, E, p, q, r, s,…

http://poj.org/problem?id=3295 题意: 判断表达式是否为永真式. 思路: 把每种情况都枚举一下. #include<iostream> #include<string> #include<cstring> using namespace std; ; int sta[MAXN]; char str[MAXN]; int p, q, r, s, t; void judge() { ; int len = strlen(str); ; i &g…

Tautology Description WFF 'N PROOF is a logic game played with dice. Each die has six faces representing some subset of the possible symbols K, A, N, C, E, p, q, r, s, t. A Well-formed formula (WFF) is any string of these symbols obeying the followin…

字母:K, A, N, C, E 表示逻辑运算 字母:p, q, r, s, t 表示逻辑变量 0 或 1 给一个字符串代表逻辑表达式,如果是永真式输出tautology 否则输出not 枚举每个逻辑变量的值,5个变量,共2^5种情况,对于每种情况都为真则为永真式. 代码: /*************************************** Problem: 3295 User: Memory: 688K Time: 0MS Language: G++ Result: Accept…

题目链接:http://poj.org/problem?id=3295 思路分析:判断逻辑表达式是否为永真式问题.根据该表达式的特点,逻辑词在逻辑变量前,类似于后缀表达式求值问题. 算法中使用两个栈,从表达式的后边开始处理表达式中每个字符:若为逻辑变量,使其入栈SR,否则从栈SR中弹出两个逻辑变量, 进行运算后的结果再入栈SR:直到处理完表达式所有的字符.(PS:使用栈可以很好的处理广义表类似的序列) 代码如下: #include <iostream> #include <stack&g…

题目链接:http://poj.org/problem?id=3295 题意: 输入由p.q.r.s.t.K.A.N.C.E共10个字母组成的逻辑表达式, 其中p.q.r.s.t的值为1(true)或0(false),即逻辑变量: K.A.N.C.E为逻辑运算符, K --> and:  x && y A --> or:  x || y N --> not :  !x C --> implies :  (!x)||y E --> equals :  x==y…