1103 Integer Factorization(30 分) The K−P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write a program to find the K−P factorization of N for any positive integers N, K an…

PAT甲级1103. Integer Factorization 题意: 正整数N的K-P分解是将N写入K个正整数的P次幂的和.你应该写一个程序来找到任何正整数N,K和P的N的K-P分解. 输入规格: 每个输入文件包含一个测试用例,它给出一行三个正整数N(<= 400), K(<= N)和P(1 <P <= 7).一行中的数字用空格分隔. 输出规格: 对于每种情况,如果解决方案存在,输出格式如下: N = n1 ^ P + ... nK ^ P 其中ni(i = 1,... K)是…

本文同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/90574720 1103 Integer Factorization (30 分)   The K−P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write…

1103 Integer Factorization (30 分)   The K−P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write a program to find the K−P factorization of N for any positive integers N, K…

The K-P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write a program to find the K-P factorization of N for any positive integers N, K and P. Input Specification: Each in…

The K−P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write a program to find the K−P factorization of N for any positive integers N, K and P. Input Specification: Each in…

The K-P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write a program to find the K-P factorization of N for any positive integers N, K and P. Input Specification: Each in…

The K-P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write a program to find the K-P factorization of N for any positive integers N, K and P. Input Specification: Each in…

暴力搜索. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; int n,k,p,top; ]; ; ],ans_num=,ans_len; void d…

题目:https://pintia.cn/problem-sets/994805342720868352/problems/994805364711604224 题意: 给定一个数n,要求从1~n中找出k个数,使得这些数的p次方之和等于n 思路: 因为n为400,所以dfs加剪枝[本来还在想dp来着] 他要求输出的方案是数字之和最大的,如果之和相等要输出字典序较大的. 所以还需维护一个数字之和. 一个剪枝的方法是从大到小进行dfs,后面被选的数一定比前面被选的要小,这里不限制的话显然会出现重复.…