1001. A+B Format (20) Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits). Input Each input file contains one test case. Each case cont…

1001 A+B Format (20)(20 分) Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits). Input Each input file contains one test case. Each case…

1001 A+B Format (20)(20 分) Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits). Input Each input file contains one test case. Each case…

1001. A+B Format (20) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four d…

题意:给两个整数a,b,计算a+b的值并每三位用逗号隔开输出(−1e6​​≤a,b≤1e6​​) AAAAAccepted code: #include<bits/stdc++.h> using namespace std; int main(){ int a,b; cin>>a>>b; int ans=a+b; ){ cout<<"-"; ans=-ans; } ; ; ; ; if(yy){ cout<<yy<<…

题目原文: Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits). Input Each input file contains one test case. Each case contains a pair of i…

/* 火星文有两位,第二位为0不输出 */ #include<stdio.h> #include<algorithm> #include<string.h> #include<ctype.h> using namespace std; char arr[20]={0}; char data[13][2][5]={ {"tret","tret"}, {"jan","tam"}, {…

一开始因为看见这题就头疼,可费了点时间. 要考虑所有元素,如果忽略外圈元素,最后一个样例过不去. 而且要求只出现一次的元素, 我没有使用map,因为当时还没学,用map储存元素会节约好多代码 #include<cstdio> #include<string.h> int M,N,TOL; int arr[1001][1001]; int da[20000000]={0}; int dir[8][2] = {{-1, -1}, {-1, 0}, {-1, 1}, {0, 1}, {1…

1018 锤子剪刀布 (20)(20 分) 大家应该都会玩“锤子剪刀布”的游戏:两人同时给出手势,胜负规则如图所示: 现给出两人的交锋记录,请统计双方的胜.平.负次数,并且给出双方分别出什么手势的胜算最大. 输入格式: 输入第1行给出正整数N(<=10^5^),即双方交锋的次数.随后N行,每行给出一次交锋的信息,即甲.乙双方同时给出的的手势.C代表“锤子”.J代表“剪刀”.B代表“布”,第1个字母代表甲方,第2个代表乙方,中间有1个空格. 输出格式: 输出第1.2行分别给出甲.乙的胜.平.负次数…

1014. 福尔摩斯的约会 (20) 大侦探福尔摩斯接到一张奇怪的字条:“我们约会吧! 3485djDkxh4hhGE 2984akDfkkkkggEdsb s&hgsfdk d&Hyscvnm”.大侦探很快就明白了,字条上奇怪的乱码实际上就是约会的时间“星期四 14:04”,因为前面两字符串中第1对相同的大写英文字母(大小写有区分)是第4个字母'D',代表星期四:第2对相同的字符是'E',那是第5个英文字母,代表一天里的第14个钟头(于是一天的0点到23点由数字0到9.以及大写字母A到N…