传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1599 find the mincost route Time Limit: 1000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 7047 Accepted Submission(s): 2736 Problem Description 杭州有N个景区,景区之间有一…
find the mincost route Time Limit: 1000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3273 Accepted Submission(s): 1320 Problem Description 杭州有N个景区,景区之间有一些双向的路来连接,现在8600想找一条旅游路线,这个路线从A点出发并且最后回到A点,假设经过的路线为V1…
转载请注明出处:http://blog.csdn.net/a1dark 分析:终于弄懂了floyd的原理.以前的理解一直肤浅.所以一做到floyd应用的题.就拙计了.其实floyd的本质DP.利用前K-1个点.便可以求出当前所成的最小环.具体实现如下(含注释): #include<stdio.h> #include<string.h> #define N 101 #define INF 0x7ffffff int mpt[N][N]; int dist[N][N]; int m,n…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1599 find the mincost route Time Limit: 1000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2530 Accepted Submission(s): 1006 Problem Description 杭州有N个景区,景区之间有一…
find the mincost route Time Limit: 1000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8771 Accepted Submission(s): 3306 Problem Description 杭州有N个景区,景区之间有一些双向的路来连接,现在8600想找一条旅游路线,这个路线从A点出发并且最后回到A点,假设经过的路线为V1…
find the mincost route Time Limit: 1000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3885 Accepted Submission(s): 1559 Problem Description 杭州有N个景区,景区之间有一些双向的路来连接,现在8600想找一条旅游路线,这个路线从A点出发并且最后回到A点,假设经过的路线为V1…