Language: Default Prime Path Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 11703   Accepted: 6640 Description The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to c…

Prime Path Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 15325   Accepted: 8634 Description The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to change the four-dig…

转载请注明出处:https://blog.csdn.net/Mercury_Lc/article/details/82697622     作者:Mercury_Lc 题目链接 题意:就是给你一个n,让你每次可以改变n的位数上的一个数,每次操作完必须是素数,要求最小次数的改变到达m. 题解:对n每一位都进行判断,找到通过最小操作次数得到m.分别要从个位.十位.百位.千位判断,在个位的时候每次只能是1.3.5.7.9,其他的改变之后都不是素数,十位.百位.千位都从0开始遍历到9,每次只要符合是素数…

Prime Path Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 27132   Accepted: 14861 Description The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to change the four-di…

Description The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to change the four-digit room numbers on their offices.  — It is a matter of security to change such things every now…

A - Prime Path(11.1.1) Time Limit:1000MS    Memory Limit:65536KB    64bit IO Format:%I64d & %I64u SubmitStatus Description The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to cha…

题意:一个4位的素数每次变动一个数位,中间过程也要上素数,问变成另一个的最小步数. 线性筛一遍以后bfs就好.我写的双向,其实没有必要. #include<cstdio> #include<iostream> #include<string> #include<cstring> #include<queue> #include<vector> #include<stack> #include<vector> #…

题意:给出n个点,m条边的无向图,每条边有一种颜色,求从结点1到结点n颜色字典序最小的最短路径. 析:首先这是一个最短路径问题,应该是BFS,因为要保证是路径最短,还要考虑字典序,感觉挺麻烦的,并不好做,事实用两次BFS, 第一次是倒序BFS,目的是得到从结点 i 到结点n的最短距离,然后再从第一个点开始到最后一个,要保证在查找时,每经过一点要让d值恰好减少1, 直到终点,这也是一个BFS,因为这个字典序在某个结点是一样的,所以是两个BFS,我超时了好几次,因为少写了一个vis, 一定要细心,…

传送门 唉考试的时候写错了两个细节调了一个多小时根本没调出来. 下来又调了半个小时才过. 其实很简单. 我们先dpdpdp出最开始最多多少个连续的aaa. 然后对于没法继续连续下去的用贪心+bfsbfsbfs来弄就行了. 技不如人,告辞. 代码: #include<bits/stdc++.h> using namespace std; int n,k,mx[2005][2005],maxA; char mp[2005][2005]; bool vis[2005][2005]; queue<…

POJ 3126 Prime Path(素数路径) Time Limit: 1000MS    Memory Limit: 65536K Description - 题目描述 The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to change the four-digit room numbers on…