# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 33: Search in Rotated Sorted Arrayhttps://oj.leetcode.com/problems/search-in-rotated-sorted-array/ Suppose a sorted array is rotated at some pivot unknown to you beforehand.(i.e., 0 1 2 4 5…
33. Search in Rotated Sorted Array Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return i…
Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise retu…
一天一道LeetCode 本系列文章已全部上传至我的github,地址: https://github.com/Zeecoders/LeetCode 欢迎转载,转载请注明出处 (一)题目 Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to…
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplic…
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplic…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/search-in-rotated-sorted-array/description/ 题目描述 Suppose an array sorted in ascending order is rotated at some pivot unknown to you before…
题目描述:在一个旋转数组中查找给定的值,其中旋转数组中不含重复值: 思路: 第一遍二分遍历,找到数组中最小值的索引: 第二遍分别对最小值左右两边的数组进行二分查找: class Solution(object): def find_min(self, nums): if not nums: return -1 left, right = 0, len(nums) - 1 while nums[left] > nums[right]: if right - left == 1: return ri…
Question: Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise retur…
1. 原题链接 https://leetcode.com/problems/search-in-rotated-sorted-array/description/ 2. 题目要求 给定一个按升序排列的数组nums[ ]和目标值target,将数组在某点处进行旋转,然后在旋转后的数组中查找与target相同的元素,存在返回其下标,不存在返回“-1”. 注意:旋转点未知! 例,{1, 2, 3, 4, 5, 6, 7}旋转后可能为: {4, 5, 6, 7,1,2, 3} {3, 4, 5, 6,…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Follow up for "Search in Rotated Sorted Array": What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function…
leetcode - 33. Search in Rotated Sorted Array - Medium descrition Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search.…
LeetCode 33 Search in Rotated Sorted Array [binary search] <c++> 给出排序好的一维无重复元素的数组,随机取一个位置断开,把前半部分接到后半部分后面,得到一个新数组,在新数组中查找给定数的下标,如果没有,返回-1.时间复杂度限制\(O(log_2n)\) C++ 我的想法是先找到数组中最大值的位置.然后以此位置将数组一分为二,然后在左右两部分分别寻找target. 二分寻找最大值的时候,因为左半部分的数一定大于nums[l],所以n…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/search-in-rotated-sorted-array-ii/description/ 题目描述: Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,0…
这4个题都是针对旋转的排序数组.其中153.154是在旋转的排序数组中找最小值,33.81是在旋转的排序数组中找一个固定的值.且153和33都是没有重复数值的数组,154.81都是针对各自问题的版本1增加了有重复数值的限制条件. 153.154都需要考虑是否旋转成和原数组一样的情况,特别的,154题还需要考虑10111和11101这种特殊情况无法使用二分查找. 33.81则不用考虑这些情况. 找最小值的题主要是利用最小值小于他前一个位置的数,同时也小于后一个位置的数 153. Find Mini…
33. Search in Rotated Sorted Array Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [,,,,,,] might become [,,,,,,]). You are given a target value to search. If found . You may assume no duplicate e…
一.题目说明 这个题目是33. Search in Rotated Sorted Array,说的是在一个"扭转"的有序列表中,查找一个元素,时间复杂度O(logn). 二.我的解答 这是一个查找,根据复杂度,我们知道只能用二分查找.但由于这个不是一个完全的有序列表,故需要改造.先写出二分查找(来源于数据结构): 二分查找: int search(vector<int>& nums, int target){ if(nums.size()<0) return…
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). You are given a target value to search. If found in the array return its index, otherwise return -1.…
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You…
Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise retu…
Question: Follow up for "Search in Rotated Sorted Array": What if duplicates are allowed? Would this affect the run-time complexity? How and why? Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e…
Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 这个和前面的一个不一样就在于可能会有重复的数字,那么判断的时候就应该注意了,遇到start…
1. Search in Rotated Sorted Array Suppose an array sorted in ascending order is rotated(轮流,循环) at some pivot(枢轴; 中心点) unknown to you beforehand(提前; 事先). (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If foun…
题目: Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 说明: 1)和1比只是有重复的数字,整体仍采用二分查找 2)方法二 : 实现:  …
Search in Rotated Sorted Array II Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 与Find Minim…
Search in Rotated Sorted Array Total Accepted: 28132 Total Submissions: 98526My Submissions Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to s…
题目: Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1…
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplic…
题目: Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1.…
一句话思路:反正只是寻找一个最小区间,断开也能二分.根据m第一次的落点,来分情况讨论. 一刷报错: 结构上有根本性错误:应该是while里面包括if,不然会把代码重复写两遍,不好. //situation1 if (nums[mid] > nums[start]) { while (start + 1 < mid) { mid = start + (end - start) / 2; if (nums[mid] == target) { return mid; } else if (nums[…