HDOJ-1017 A Mathematical Curiosity(淼)】的更多相关文章

Problem Description Given two integers n and m, count the number of pairs of integers (a,b) such that 0 < a < b < n and (a^2+b^2 +m)/(ab) is an integer. This problem contains multiple test cases! The first line of a multiple input is an integer N…
A Mathematical Curiosity Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 41995    Accepted Submission(s): 13502 Problem Description Given two integers n and m, count the number of pairs of integ…
A Mathematical Curiosity Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 25871    Accepted Submission(s): 8174 Problem Description Given two integers n and m, count the number of pairs of integ…
//2014.10.17    01:19 //题意: //先输入一个数N,然后分块输入,每块输入每次2个数,n,m,直到n,m同一时候为零时  //结束,当a和b满足题目要求时那么这对a和b就是一组 //注意: //每一块的输出中间有一个回车 A Mathematical Curiosity Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s…
题目:pid=1017">点击打开链接 #include<stdio.h> int main() { int t; scanf("%d",&t); while(t--) { int a=0; int m,n; while(scanf("%d%d",&n,&m)) { if(m==0&&n==0) break; a++; int i,j,k,z=0; for(i=1;i<n;i++) for(j…
题目简单,格式酸爽.. #include <iostream> using namespace std; int ans,n,m,p; int main() { cin>>p; while(p--) { ; while(~scanf("%d%d",&n,&m)&&(n+m)) { ans=; ;i<n;i++) { ;j<n;j++) { ) ans++; } } printf("Case %d: %d\n&…
题目链接 Problem Description Given two integers n and m, count the number of pairs of integers (a,b) such that 0 < a < b < n and (a^2+b^2 +m)/(ab) is an integer. This problem contains multiple test cases! The first line of a multiple input is an inte…
解题报告:输入两个数,n和m,求两个数a和b满足0<a<b<n,并且(a^2+b^2+m) % (a*b) =0,这样的a和b一共有多少对.注意这里的b<n,并不可以等于n. 简单的数学题,要注意的就是格式,这题TM描述的真烂,注意每组测试数据之后有一个空行,但最后一组测试数据之后没有空行. #include<cstdio> int main() { int T,n,m; scanf("%d",&T); while(T--) { ; whil…
#include<stdio.h> int main() { int N; int n,m; int a,b; int cas; scanf("%d",&N); while(N--) { cas=1;//必须在这儿初始化cas,坑 while(scanf("%d%d",&n,&m),n||m) { int count=0; for(a = 1; a < n; a++)//穷举法 { for(b = a + 1; b <…
Problem Description Given two integers n and m, count the number of pairs of integers (a,b) such that 0 < a < b < n and (a^2+b^2 +m)/(ab) is an integer. This problem contains multiple test cases! The first line of a multiple input is an integer N…
传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1017 A Mathematical Curiosity Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 47658    Accepted Submission(s): 15285 Problem Description Given two…
A Mathematical Curiosity Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 31177 Accepted Submission(s): 9988 Problem Description Given two integers n and m, count the number of pairs of integers (a…
A Mathematical Curiosity Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 87   Accepted Submission(s) : 23 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Given two in…
http://acm.hdu.edu.cn/showproblem.php?pid=1017 # include <stdio.h> int find(int n, int m) { int count = 0; for(int i = 1; i < n; i++) { for(int j = i + 1; j < n; j++) { if(((i * i) + (j * j) + m) % (i * j) == 0) count++; } } return count; } in…
 此题不难就是输出格式麻烦 #include<stdio.h>  int main(){        int T;   scanf("%d",&T);     while(T--)      {      int n,m,num=0;     while(scanf("%d %d",&n,&m)&&n!=0)     {                 int a,b,sum=0;          for(…
Problem Description Given two integers n and m, count the number of pairs of integers (a,b) such that 0 < a < b < n and (a^2+b^2 +m)/(ab) is an integer. This problem contains multiple test cases! The first line of a multiple input is an integer N…
方法:枚举 做这道题,在第十行的位置WA了很多次,(n || m)不能写成(n + m),m可能是负数,一直没注意到,导致不停的WA....... #include <stdio.h> int main() { int T,n,m,a,b,ans,p = 0; scanf("%d",&T); while(T--) { if(p ++) printf("\n"); int num = 1; while(scanf("%d%d",…
题目链接 /* Name: Copyright: Author: Date: 2018/5/3 16:32:15 Description: */ #include <iostream> #include <cstdio> using namespace std; int n, m; bool equals(int a, int b) { )return true; return false; } int main() { int t; cin>>t; while (t-…
A Mathematical Curiosity http://acm.hdu.edu.cn/showproblem.php?pid=1017 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 22366    Accepted Submission(s): 7021 Problem Description Given two integ…
杭电ACM分类: 1001 整数求和 水题1002 C语言实验题——两个数比较 水题1003 1.2.3.4.5... 简单题1004 渊子赛马 排序+贪心的方法归并1005 Hero In Maze 广度搜索1006 Redraiment猜想 数论:容斥定理1007 童年生活二三事 递推题1008 University 简单hash1009 目标柏林 简单模拟题1010 Rails 模拟题(堆栈)1011 Box of Bricks 简单题1012 IMMEDIATE DECODABILITY…
acm之pku题目分类 对ACM有兴趣的同学们可以看看 DP:  1011   NTA                 简单题  1013   Great Equipment     简单题  1024   Calendar Game       简单题  1027   Human Gene Functions   简单题  1037   Gridland            简单题  1052   Algernon s Noxious Emissions 简单题  1409   Commun…
以下是poj百道水题,新手可以考虑从这里刷起 搜索1002 Fire Net1004 Anagrams by Stack1005 Jugs1008 Gnome Tetravex1091 Knight Moves1101 Gamblers1204 Additive equations 1221 Risk1230 Legendary Pokemon1249 Pushing Boxes 1364 Machine Schedule1368 BOAT1406 Jungle Roads1411 Annive…
转载:from http://blog.csdn.net/qq_28236309/article/details/47818349 基础题:1000.1001.1004.1005.1008.1012.1013.1014.1017.1019.1021.1028.1029. 1032.1037.1040.1048.1056.1058.1061.1070.1076.1089.1090.1091.1092.1093. 1094.1095.1096.1097.1098.1106.1108.1157.116…
A Mathematical Curiosity Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Problem Description Given two integers n and m, count the number of pairs of integers (a,b) such that 0 < a < b < n and (a^2+b^2 +m)/(ab)…
HDOJ 题目分类 //分类不是绝对的 //"*" 表示好题,需要多次回味 //"?"表示结论是正确的,但还停留在模块阶 段,需要理解,证明. //简单题看到就可以敲的 1000:    入门用: 1001:    用高斯求和公式要防溢出 1004:1012: 1013:    对9取余好了 1017:1021: 1027:    用STL中的next_permutation() 1029:1032:1037:1039:1040:1056:1064:1065: 10…
HDOJ 题目分类 /* * 一:简单题 */ 1000:    入门用:1001:    用高斯求和公式要防溢出1004:1012:1013:    对9取余好了1017:1021:1027:    用STL中的next_permutation()1029:1032:1037:1039:1040:1056:1064:1065:1076:    闰年 1084:1085:1089,1090,1091,1092,1093,1094, 1095, 1096:全是A+B1108:1157:1196:1…
FatMouse' Trade Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 56784    Accepted Submission(s): 19009 Problem Description FatMouse prepared M pounds of cat food, ready to trade with the cats g…
Nasty Hacks Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3049    Accepted Submission(s): 2364 Problem Description You are the CEO of Nasty Hacks Inc., a company that creates small pieces of…
Box of Bricks Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 5994    Accepted Submission(s): 2599 Problem Description Little Bob likes playing with his box of bricks. He puts the bricks one up…
Problem Description Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color…