Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positions clock-wise, we define a "rotation function" F on A as follow: F(k) = 0 * Bk[0] + 1 * Bk[1] + ... + (n-1) * Bk[n-1]. Ca…

Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positions clock-wise, we define a "rotation function" F on A as follow: F(k) = 0 * Bk[0] + 1 * Bk[1] + ... + (n-1) * Bk[n-1]. Ca…

Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positions clock-wise, we define a "rotation function" F on A as follow: F(k) = 0 * Bk[0] + 1 * Bk[1] + ... + (n-1) * Bk[n-1]. Ca…

Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A kpositions clock-wise, we define a "rotation function" F on A as follow: F(k) = 0 * Bk[0] + 1 * Bk[1] + ... + (n-1) * Bk[n-1]. Cal…

［抄题］: Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positions clock-wise, we define a "rotation function" F on A as follow: F(k) = 0 * Bk[0] + 1 * Bk[1] + ... + (n-1) * Bk[n-…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/rotate-function/description/ 题目描述: Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positio…

#-*- coding: UTF-8 -*- #超时#        lenA=len(A)#        maxSum=[]#        count=0#        while count<lenA:#            tmpSum=0#            for i in xrange(lenA):#                tmpSum+=i*A[i-count]#            maxSum.append(tmpSum)#            coun…

一开始没察觉到0123 3012 2301 而不是 0123 1230 2301 的原因,所以也没找到规律,一怒之下brute-force.. public int maxRotateFunction(int[] A) { if(A.length == 0) return 0; int res = Integer.MIN_VALUE; for(int i = 0; i < A.length;i++) { int temp = 0; for(int j = i,total = 0; total <…

给定一个长度为 n 的整数数组 A .假设 Bk 是数组 A 顺时针旋转 k 个位置后的数组,我们定义 A 的“旋转函数” F 为:F(k) = 0 * Bk[0] + 1 * Bk[1] + ... + (n-1) * Bk[n-1].计算F(0), F(1), ..., F(n-1)中的最大值.注意:可以认为 n 的值小于 105.示例:A = [4, 3, 2, 6]F(0) = (0 * 4) + (1 * 3) + (2 * 2) + (3 * 6) = 0 + 3 + 4 + 18…

1.关于leetcode 这是第一篇关于leetcode的题解,就先扯点关于leetcode的话. 其实很早前就在博客园看到过leetcode一些题解,总以为跟一般OJ大同小异,直到最近点开了一篇博文Leetcode 编程训练,无意间点进leetcode的主页看了下,乖乖,居然能用JavaScript提交代码(还能用python.ruby等)!瞬间来了兴趣,一口气把几十道水题都切完了,代码放在了github,有兴趣的可以参考或者帮忙review一下.对于个人认为有意思的题目,楼主也会时不时地写些…