Given an array of integers nums, write a method that returns the "pivot" index of this array. We define the pivot index as the index where the sum of the numbers to the left of the index is equal to the sum of the numbers to the right of the ind…

Given an array of integers nums, write a method that returns the "pivot" index of this array. We define the pivot index as the index where the sum of the numbers to the left of the index is equal to the sum of the numbers to the right of the ind…

Given an array of integers nums, write a method that returns the "pivot" index of this array. We define the pivot index as the index where the sum of the numbers to the left of the index is equal to the sum of the numbers to the right of the ind…

Given an array of integers nums, write a method that returns the "pivot" index of this array. We define the pivot index as the index where the sum of the numbers to the left of the index is equal to the sum of the numbers to the right of the ind…

Given an array of integers nums, write a method that returns the "pivot" index of this array. We define the pivot index as the index where the sum of the numbers to the left of the index is equal to the sum of the numbers to the right of the ind…

［抄题］: Given an array of integers nums, write a method that returns the "pivot" index of this array. We define the pivot index as the index where the sum of the numbers to the left of the index is equal to the sum of the numbers to the right of t…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3742 访问. 给定一个整数类型的数组 nums,请编写一个能够返回数组"中心索引"的方法. 我们是这样定义数组中心索引的:数组中心索引的左侧所有元素相加的和等于右侧所有元素相加的和. 如果数组不存在中心索引,那么我们应该返回 -1.如果数组有多个中心索引,那么我们应该返回最靠近左边的那一个. 输入: nums = [1, 7, 3, 6, 5, 6]…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 先求和,再遍历 日期 题目地址:https://leetcode.com/problems/find-pivot-index/description/ 题目描述 Given an array of integers nums, write a method that returns the "pivot" index of this arr…

problem 724. Find Pivot Index 题意:先求出数组的总和,然后维护一个当前数组之和curSum,然后对于遍历到的位置,用总和减去当前数字,看得到的结果是否是curSum的两倍,是的话,那么当前位置就是中枢点,返回即可:否则就将当前数字加到curSum中继续遍历,遍历结束后还没返回,说明没有中枢点,返回-1即可. solution: 注意,不管有几种方式,最后的结果都是从最左边开始的那个结果,那么我们就直接从最左边开始计算,返回第一个满足条件的即可. class Solu…

leetcode 724. Find Pivot Index 题目描述:在数组中找到一个值,使得该值两边所有值的和相等.如果值存在,返回该值的索引,否则返回-1 思路:遍历两遍数组,第一遍求出数组的和,第二遍开始,保存左边所有的值的和,当左边值的和的2倍加上当前值等于数组和时,就是要找的索引.时间复杂度为o(n),空间复杂度为o(1). class Solution(object): def pivotIndex(self, nums): """ :type nums: Li…