题目 提供一个非容斥做法--\(FWT\) 我们发现我们要求的东西就是一个背包,只不过是在\(and\)意义下的 自然有 \[dp_{i,j}=\sum_{k\&a_i=j}dp_{i-1,k}+dp_{i-1,j}\] 我们发现这个柿子本质上就是一个和卷积 于是两边取\(fwt\),我们就可以得到一个暴力\(fwt\)的代码 for(re int i=1;i<=n;i++) { memset(A,0,sizeof(A)); A[a[i]]=1;Fwtand(A,1); for(re int…

题目描述: 解题思路: 给定两个链表(代表两个非负数),数字的各位以正序存储,将两个代表数字的链表想加获得一个新的链表(代表两数之和). 如(7->2->4->3)(7243) + (5->6->4)(564) = (7->8->0->7)(7807) 此题与[LeetCode2]Add Two Numbers解决思路类似,不同之处在于此题的数字以正序存储,故需要借助栈. Java代码: import java.util.Stack; //public cl…

[LeetCode]386. Lexicographical Numbers 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/lexicographical-numbers/description/ 题目描述: Given an integer n, return 1 - n in lexicogra…

题目描述: Compare two version numbers version1 and version2. If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0. You may assume that the version strings are non-empty and contain only digits and the . character. The .…

题目描述: You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input: (2 -> 4 -> 3) + (5 -> 6…

Compare two version numbers version1 and version2.If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0. You may assume that the version strings are non-empty and contain only digits and the . character.The . characte…

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input: (2 -> 4 -> 3) + (5 -> 6 ->…

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input: (2 -> 4 -> 3) + (5 -> 6 ->…

题目描述: Given a non-negative integer n, count all numbers with unique digits, x, where 0 ≤ x < 10n. 解题分析: 题目要就就是找出 0≤ x < 10n中各位数字都不相同的数的个数.要接触这道题只需要理解: 1.设f(n)表示n为数字中各位都不相同的个数,则有countNumbersWithUniqueDigits(n)=f(1)+f(2)+……+f(n)=f(n)+countNumbersWithU…

一.前言 前面已经学习了Scala中的String,接着学习Scala的Numbers. 二.Numbers 在Scala中,所有的数字类型,如Byte,Char,Double,Float,Int,Long,Short都是对象,这七种数字类型继承AnyVal特质,这七种数字类型与其在Java中有相同的范围,而Unit和Boolean则被认为是非数字值类型,Boolean有false和true两个值,你可以获取到各个数字类型的最值. 复杂的数字和日期 如果需要更强大的数类,可以使用spire,sc…