LC 898. Bitwise ORs of Subarrays

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LC 898. Bitwise ORs of Subarrays

We have an array A of non-negative integers. For every (contiguous) subarray B = [A[i], A[i+1], ..., A[j]] (with i <= j), we take the bitwise OR of all the elements in B, obtaining a result A[i] | A[i+1] | ... | A[j]. Return the number of possible re…

[LeetCode] 898. Bitwise ORs of Subarrays 子数组按位或操作

We have an array A of non-negative integers. For every (contiguous) subarray B = [A[i], A[i+1], ..., A[j]] (with i <= j), we take the bitwise OR of all the elements in B, obtaining a result A[i] | A[i+1] | ... | A[j]. Return the number of possible re…

898. Bitwise ORs of Subarrays

We have an array A of non-negative integers. For every (contiguous) subarray B = [A[i], A[i+1], ..., A[j]] (with i <= j), we take the bitwise OR of all the elements in B, obtaining a result A[i] | A[i+1] | ... | A[j]. Return the number of possible re…

【LeetCode】898. Bitwise ORs of Subarrays 解题报告（Python）

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录题目描述题目大意解题方法动态规划相似题目参考资料日期题目地址:https://leetcode.com/problems/bitwise-ors-of-subarrays/description/ 题目描述 We have an array A of non-negative integers. For every (contiguous) subarray B =…

[Swift]LeetCode898. 子数组按位或操作 | Bitwise ORs of Subarrays

We have an array A of non-negative integers. For every (contiguous) subarray B = [A[i], A[i+1], ..., A[j]] (with i <= j), we take the bitwise OR of all the elements in B, obtaining a result A[i] | A[i+1] | ... | A[j]. Return the number of possible re…

子序列的按位或 Bitwise ORs of Subarrays

2018-09-23 19:05:20 问题描述: 问题求解: 显然的是暴力的遍历所有的区间是不可取的,因为这样的时间复杂度为n^2级别的,对于规模在50000左右的输入会TLE. 然而,最后的解答也可以看作是一个暴力求解,也就是用Set来保存以当前数为结尾的左右可能解,在下一轮中遍历上一轮的所有解并进行或操作. 这里有个难以一下想到的地方就是,乍一看,这个时间复杂度依然是平方级别的,但是实际上,这里的时间复杂度是n级别的,因为Set中后一个数中的1完全覆盖前一个数,因此,最多只有不超过30个数…