结束了三分搜索的旅程 我开始迈入深搜的大坑.. 首先是一道比较基础的深搜题目(还是很难理解好么) POJ 1564 SUM IT UP 大体上的思路无非是通过深搜来进行穷举.匹配 为了能更好地理解深搜 可以尝试去画一下二叉树理解一下,查看遍历的路径 代码还是百度到别人的自己再参悟- -佩服别人的功底啊 先上代码: /*POJ 1546 Sum it up*/ # include<iostream> # include<algorithm> # include<cstdio&g…
按字典序输出所有在123..n之间插入'+','-',' '结果为0的表达式.. http://train.usaco.org/usacoprob2?a=jUh88pMwCSQ&S=zerosum /* TASK:zerosum LANG:C++ */ #include<cstdio> #include<string> #include<algorithm> using namespace std; #define N 15 int n; int k[N],cn…
题目链接 Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how many quadruplet (a, b, c, d ) ∈ A x B x C x D are such that a + b + c + d = 0 . In the following, we assume that all lists have…