一个很常见的问题,找出一个数组中和为给定值的两个数的下标.为了简单一般会注明解只有一个之类的. 最容易想到的方法是循环遍历,这里就不说了. 在JS中比较优雅的方式是利用JS的对象作为hash的方式: var twoSum = function(nums, target) { var hash = {}; var i; for (var i = 0; i < nums.length; i++ ) { if (typeof hash[nums[i]] !== "undefined")…

Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that…

Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that…

LeetCode: 1. twoSum 题目描述 Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution. Example: Given nums = [2, 7, 11, 15], target = 9, Becau…

题目链接:http://www.lintcode.com/zh-cn/problem/two-sum/ 给一个整数数组,找到两个数使得他们的和等于一个给定的数target. 备份一份,然后排序.搞两个指针分别从左从右开始扫描,每次判断这两个数相加是不是符合题意,如果小了,那就把左边的指针向右移,同理右指针.然后在备份的数组里找到位置. class Solution: """ @param numbers : An array of Integer @param target…

今天注册了大名鼎鼎的LeetCode,做了一道最简单的算法题目: Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution. Example: Given nums = [2, 7, 11, 15], target =…

题目: Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note t…

Description Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. 题意 给定一个数组,和一个定值,找出数组元素的两…

Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution. Example: Given nums = [2, 7, 11, 15], target = 9, Because nums[0] + nums[1] = 2…

package org.lep.leetcode.twosum; import java.util.Arrays; import java.util.HashMap; import java.util.Map; /** * source:https://leetcode.com/problems/two-sum-ii-input-array-is-sorted/#/description * Created by lverpeng on 2017/6/21. * * Given an array…

1. Two Sum Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. Example: Given nums = [2,…

记录被LeetCode虐的日子 第一种方法:使用枚举 /** * Note: The returned array must be malloced, assume caller calls free(). */ int* twoSum(int* nums, int numsSize, int target) { int *result = (int*)malloc(2 * sizeof (int)); //申请内存 int i = 0; int j = 0; if(sizeof(nums) <…

在一个不重复的数组中,统计有多少组两个元素相加得0. 这里使用三种方式实现,并统计他们各自花费的时间: import java.util.Arrays; import java.util.HashMap; import java.util.Random; public class TwoSum { private static int N = 100000; private static int[] a = new int[N]; private static Random random = n…

package leetcode; import java.util.HashMap; import java.util.Map; /** * @author mercy *Example: *Given nums = [2, 7, 11, 15], target = 9, *Because nums[0] + nums[1] = 2 + 7 = 9, *return [0, 1]. */ public class TwoSum { public static void main(String[…

题目: Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note t…

今天无意中看到一个题目,也不是很难,就想着用python实现以下: 题目是数组中的两个数相加等于输入的一个target,然后输出数组的下标. 比如: [1,2,3,4,5,6] target=7  返回[1,4] 主要是坑就是避免有重复的数字 代码如下 # -*- coding:utf -8 -*- def TwoSum(nums,target): if len(nums) <0: return False for m in nums: n = target-m if n in nums: if…

题目: Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. Example: Given nums = [, , , ],…

1). two-sum Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Pleas…

Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. Example: Given nums = [2, 7, 11, 15]…

class Solution { public: vector<int> twoSum(vector<int>& nums, int target) { vector<int>result; int i,j,k; map<int,int>h; ;i<nums.size();i++) { if(!h.count(nums[i])) h[nums[i]]=i+; k=h[target-nums[i]]; &&k!=i+) { res…

class Solution { public: vector<int> twoSum(vector<int>& nums, int target) { vector<int> twoSum1(2); map<int,int> mValueIdex; map<int,int>::iterator it; bool flag=0; for(int i=0;i<nums.size();i++) { //两个一样. if(nums[i]=…

LeetCode 两数之和 给定一个整数数组,返回两个数字的索引,使它们相加到特定目标. 您可以假设每个输入只有一个解决方案,并且您可能不会两次使用相同的元素. 更多文章查看个人博客 个人博客地址:twoSum 两数之和 [JAVA实现] 方法一 使用双重循环两两相加判断是否等于目标值 public List<String> twoSum2(int[] arr, int sum) { if (arr == null || arr.length == 0) { return new ArrayL…

两数之和 (简单) 题目描述 给定一个整数数组和一个目标值,找出数组中和为目标值的两个数: 你可以假设每个输入只对应一种答案,且同样的元素不能被重复利用. 例如: 给定 nums = [2,7,11,15] ,target = 9 因为 nums[0] + nums[1] = 9: 因此返回 [0,1]: v1.0代码如下: 正数.0或重复值通过测试: 异常用例: [-1, -2, -3, -4, -5] -8; 输出 [] /** * @param {number[]} nums * @par…

""" Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. Example: Given nums =…

Two Sum 系列问题在 LeetCode 上有好几道,这篇文章就挑出有代表性的几道,介绍一下这种问题怎么解决. TwoSum I 这个问题的最基本形式是这样:给你一个数组和一个整数 target,可以保证数组中存在两个数的和为 target,请你返回这两个数的索引. 比如输入 nums = [3,1,3,6], target = 6,算法应该返回数组 [0,2],因为 3 + 3 = 6. 这个问题如何解决呢?首先最简单粗暴的办法当然是穷举了: int[] twoSum(int[] nums…

1.普通数组找两个数,哈希表建立数值和下标的映射,遍历时一边判断一边添加 /* 哇,LeetCode的第一题...啧啧 */ public int [] twoSum(int[] nums, int target) { /* 两个数配合组成target 建立值和下标的映射,遍历数组时一边判断是否有另一半,一边添加新映射到哈希表 */ Map<Integer,Integer> map = new HashMap<>(); for (int i = 0; i < nums.len…

编译的版本比运行的版本高. 两台电脑,一个装的是jdk1.7,另一个是1.8,在1.8上运行之后,上传到github然后1.7的拉下来,再运行出现了上述错误. 解决方式:设置如下…

代码的(判断nums[i]或者是target-nums[i]都可以):…

Let's begin with a naive method. We first need to sort the array A[n]. And we want to solve the problem by iterating through A from beginning and ending. Then, if the sum is less than the target, we move the leading pointer to next right. When the su…

my answer: ​​​​出现的问题:倒数第二行and i !=s这种情况没有考虑进去,以后要思考全面些…