描述 Given a sorted linked list, delete all duplicates such that each element appear only once. Example 1: Input: 1->1->2Output: 1->2Example 2: Input: 1->1->2->3->3Output: 1->2->3 有序链表去重. 解析 移除给定有序链表的重复项,那么我们可以遍历这个链表,每个结点和其后面的结点比较…

[LeetCode] Remove Duplicates from Sorted Array 有序数组中去除重复项 描述 Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this…

Given a sorted array nums, remove the duplicates in-place such that duplicates appeared at most twice and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra mem…

Given a sorted array nums, remove the duplicates in-place such that duplicates appeared at most twice and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra mem…

Follow up for "Remove Duplicates":What if duplicates are allowed at most twice? For example,Given sorted array A = [1,1,1,2,2,3], Your function should return length = 5, and A is now [1,1,2,2,3]. 这道题是之前那道Remove Duplicates from Sorted Array 有序数组中…

题意:从有序链表中删除重复节点. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* deleteDuplicates(ListNode* head) { if(head == NULL || head…

给定一个有序数组,你需要原地删除其中的重复内容,使每个元素只出现一次,并返回新的长度.不要另外定义一个数组,您必须通过用 O(1) 额外内存原地修改输入的数组来做到这一点.示例:给定数组: nums = [1,1,2],你的函数应该返回新长度 2, 并且原数组nums的前两个元素必须是1和2不需要理会新的数组长度后面的元素详见:https://leetcode.com/problems/remove-duplicates-from-sorted-array/description/ Java实现…

本文始发于个人公众号:TechFlow,原创不易,求个关注 今天是LeetCode专题的第51篇文章,我们来看LeetCode第82题,删除有序链表中的重复元素II(Remove Duplicates from Sorted List II). 这题官方给出的难度是Medium,点赞1636,反对107,通过率在36.3%左右.根据我们之前的分析,这题的难度适中,并且质量很高,好评如潮.实际上也的确如此,这题算法本身并不难,但是想要完整没有bug地实现并不容易,我们一起来看看. 题意 给定一个有…

Given a sorted linked list, delete all duplicates such that each element appear only once. Example 1: Input: 1->1->2 Output: 1->2 Example 2: Input: 1->1->2->3->3 Output: 1->2->3 这道题让我们移除给定有序链表的重复项,那么可以遍历这个链表,每个结点和其后面的结点比较,如果结点值相…

Given a sorted linked list, delete all duplicates such that each element appear only once. Example 1: Input: 1->1->2 Output: 1->2 Example 2: Input: 1->1->2->3->3 Output: 1->2->3 题意: 有序链表去重 思路: 代码: class Solution { public ListNod…

给定一个排序链表,删除所有重复的元素使得每个元素只留下一个.案例:给定 1->1->2,返回 1->2给定 1->1->2->3->3,返回 1->2->3详见:https://leetcode.com/problems/remove-duplicates-from-sorted-list/description/ Java实现: 递归实现: /** * Definition for singly-linked list. * public class…

Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 题目标签:Linked List 题目给了我们一个 list,让我们去除中间的重复项. 设一个 cursor = head…

题目描述: Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 代码如下: 代码一,正常解法: /** * Definition for singly-linked list…

Given a sorted linked list, delete all duplicates such that each element appear only once. Example 1: Input: 1->1->2 Output: 1->2 Example 2: Input: 1->1->2->3->3 Output: 1->2->3 利用dummy head,将head 和head.next 比较(如果head.next存在的话),…

Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 设置2个指针,cur 和next. 当cur的值与next的值相等时,cur.next= next.next   更新ne…

Given a sorted linked list, delete all duplicates such that each element appear only once. For example, Given 1->1->2, return 1->2. Given 1->1->2->3->3, return 1->2->3. 思路:此题与上一题异曲同工,详细解法例如以下: /** * Definition for singly-linked…

就是将链表中的重复元素去除 我的方法很简单就是如果链表的前后元素相同的话,将后一个元素删除 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* deleteDuplicates(ListNode* he…

Given a sorted array nums, remove the duplicates in-place such that duplicates appeared at most twice and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra mem…

https://leetcode.com/problems/remove-duplicates-from-sorted-array-ii/discuss/27976/3-6-easy-lines-C%2B%2B-Java-Python-Ruby 描述 Follow up for "Remove Duplicates":What if duplicates are allowed at most twice? For example,Given sorted array A = [1,1…

Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinctnumbers from the original list. Example 1: Input: 1->2->3->3->4->4->5 Output: 1->2->5 Example 2: Input: 1->1->1->2->3 Output…

Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example,Given 1->2->3->3->4->4->5, return 1->2->5.Given 1->1->1->2->3, return 2->3.…

203题是在链表中删除一个固定的值,83题是在链表中删除重复的数值,但要保留一个:82也是删除重复的数值,但重复的都删除,不保留. 比如[1.2.2.3],83题要求的结果是[1.2.3],82题要求的结果是[1,3]. 这种题用递归去做比较方便思考,特别是这种重复的数值.递归就是只遍历当前的节点的情况,之前的不用管,之后的以当前节点为出发点思考问题. 203. Remove Linked List Elements class Solution { public: ListNode* remo…

83. Remove Duplicates from Sorted List Total Accepted: 94387 Total Submissions: 264227 Difficulty: Easy 题目意思:如今有一个已经排好顺序的链表,删除全部反复的节点.使每一个节点都仅仅出现一次! Given a sorted linked list, delete all duplicates such that each element appear only once. For exampl…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 判断相邻节点是否相等 使用set 使用列表 递归 日期 [LeetCode] 题目地址:https://leetcode.com/problems/remove-duplicates-from-sorted-list/ Total Accepted: 114584 Total Submissions: 311665 Difficulty: Easy…

83. Remove Duplicates from Sorted List[easy] Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 解法一: /** * Defin…

LeetCode 80 Remove Duplicates from Sorted Array II [Array/auto] <c++> 给出排序好的一维数组,如果一个元素重复出现的次数大于两次,删除多余的复制,返回删除后数组长度,要求不另开内存空间. C++ 献上自己丑陋无比的代码.相当于自己实现一个带计数器的unique函数 class Solution { public: int removeDuplicates(std::vector<int>& nums) {…

LeetCode 26 Remove Duplicates from Sorted Array [Array/std::distance/std::unique] <c++> 给出排序好的一维数组,删除其中重复元素,返回删除后数组长度,要求不另开内存空间. C++ 很简单的题目,但是第一发RE了,找了很久问题出在哪.最后单步调试发现vector.size()返回值是unsigned型的.unsigned型和int型数据运算结果还是unsigned型的.这就导致当数组为空时,nums.size(…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given a sorted linked list, delete all duplicates such that each element appear only once. For example, Given 1->1->2, return 1->2. Given 1->1->2-&…

哈哈,我又来了.昨天发现题目太简单就没有放上来,今天来了一道有序链表的题.题目如下: Given a sorted linked list, delete all duplicates such that each element appear only once. For example, Given 1->1->2, return 1->2. Given 1->1->2->3->3, return 1->2->3. 题目分析:简单来说就是去除有序链…

Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 移除有序链表中的重复项需要定义个指针指向该链表的第一个元素,然后第一个元素和第二个元素比较,如果重复了,则删掉第二个元素,…