HDU 6126 Give out candies(网络流)】的更多相关文章

hdu 6126 Give out candies(最小割) 题意: 有\(n\)个小朋友,标号为\(1\)到\(n\),你要给每个小朋友至少\(1\)个且至多\(m\)个的糖果.小朋友们共提出\(k\)个要求,每个要求包括三个整数\(x,y,z\),表示\(x\)号小朋友得到的糖果数减去\(y\)号小朋友得到的糖果数,结果应当不大于\(z\).如果你给\(i\)号小朋友\(j\)颗糖果,他会获得\(w_{i,j}\) 的满意度,你需要最大化所有小朋友的满意度之和.\(1\leq n,m\leq…
题目给出n,m,k 然后给出n*m的矩阵a[i][j]代表第i个人在获得j 颗糖果能得到的满足值, 然后k是k行每行输入三个整数x,y,z     ,x,y,z表示一组限制表示第x个人分到的糖数减去第y个人分到的糖数不大于z: 数据小,考虑网络流(*^_^*) 因为题目的z可能为负数,而网络流建边容量时的负数概念不能被覆盖,所有建立一个等效‘0’位置的值,sign=1000(大于负数绝对值就行) 对于每个人,我们把他拆成m个点,源点向第一个点连inf流量的边,而剩余的点连sign-a[][]中存…
Give out candies Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 218    Accepted Submission(s): 66 Problem Description There are n children numbered 1 to n, and HazelFan's task is to give out…
HDU 3081 Marriage Match II (网络流,最大流,二分,并查集) Description Presumably, you all have known the question of stable marriage match. A girl will choose a boy; it is similar as the game of playing house we used to play when we are kids. What a happy time as…
HDU 3338 Kakuro Extension (网络流,最大流) Description If you solved problem like this, forget it.Because you need to use a completely different algorithm to solve the following one. Kakuro puzzle is played on a grid of "black" and "white" ce…
HDU 4280 Island Transport(网络流,最大流) Description In the vast waters far far away, there are many islands. People are living on the islands, and all the transport among the islands relies on the ships. You have a transportation company there. Some route…
题目链接: Hdu 5407 CRB and Candies 题目描述: 给出一个数n,求lcm(C(n,0),C[n,1],C[n-2]......C[n][n-2],C[n][n-1],C[n][n])%(1e9+7)是多少? 解题思路: 刚开始的时候各种开脑洞,然后卡题卡的风生水起.最后就上了数列查询这个神奇的网站,竟然被我找到了!!!!就是把题目上给的问题转化为求lcm(1, 2, 3, 4 ...... n-2, n-1, n, n-1) / (n+1),扎扎就打了两个表一个lcm[n…
看了标程的压位,才知道压位也能很容易写- - /* HDU 6085 - Rikka with Candies [ 压位 ] | 2017 Multi-University Training Contest 5 题意: 给定 A[N], B[N], Q 个 k 对于每个k, 求 A[i] % B[j] == k 的 (i,j)对数 限制 N, Q <=50000 分析: 对于每个 B[i] 按其倍数分块,则对于 A[j] ∈ [x*B[i],(x+1)*B[i]) , A[j]%B[i] = A…
题意 有$n​$个小朋友,给每个人分$1~m​$个糖果,有k个限制 限制形如$(x,y,z)​$ 表示第$x​$个人分到的糖数减去第$y​$个人分到的糖数不大于$z​$,给第$i​$个人$j​$颗糖获得的满意度为$w_{i,j}​$,问总满意度最大值 点$(i,j)$表示第$i$个人分$j$个糖,当这个点属于$s$集合成立,因为是求满意度最大值,所以负权建边,同时加上个最大值$Max$使得满足最大流模板,假设不考虑限制,对于每一个$i$,连边$(i,j)\rightarrow (i,j+1),j…
题意: 给定n, m, k 以下n个整数 a[n] 以下m个整数 b[n] 用数字[0,k]构造一个n*m的矩阵 若有唯一解则输出这个矩阵.若有多解输出Not Unique,若无解输出Impossible 思路:网络流,,. n行当成n个点,m列当成m个点 从行-列连一条流量为k的边,然后源点-行连一条a[i]的边, 列-汇点 流量为b[i] 瞎了,该退役了 T^T #include<stdio.h> #include<string.h> #include<iostream&…