题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3007 Each person had do something foolish along with his or her growth.But,when he or she did this that time,they could not predict that this thing is a mistake and they will want this thing would rather…

题意:给出n个点,求最小包围圆. 解法:这两天一直在学这个神奇的随机增量算法……看了这个http://soft.cs.tsinghua.edu.cn/blog/?q=node/1066之后自己写了好久一直写不对……后来在计算几何的模板上找到了…………orz膜拜一下 代码: #include<stdio.h> #include<iostream> #include<algorithm> #include<string> #include<string.h…

今天学习了一下最小圆覆盖, 看了一下午都没看懂, 晚上慢慢的摸索这代码,接合着别人的讲解, 画着图跟着代码一步一步的走着,竟然有些理解了. 最小圆覆盖: 给定n个点, 求出半径最小的圆可以把这些点全部包围, 可以在圆的边界上 下面是我的个人理解. 如果不对, 还请路过大牛指出 先找一个点, 让圆心等于这个点的坐标, 半径等于0, 显然这个对的, 接着找下一个点, 如果只有两个点的话, 那么最小的圆一定是以他们为直径做圆, 接着找第三个点, 如果第三个点在园内或者在边界上, 那么不用更新当前的最小…

Buried memory Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4067    Accepted Submission(s): 2171 Problem Description Each person had do something foolish along with his or her growth.But,when…

Problem Description Each person had do something foolish along with his or her growth.But,when he or she did this that time,they could not predict that this thing is a mistake and they will want this thing would rather not happened.The world king Sco…

#include<iostream> #include<cstdio> #include<cmath> #include<algorithm> using namespace std; const int N=505; int n; double r; struct dian { double x,y; dian(double X=0,double Y=0) { x=X,y=Y; } dian operator + (const dian &a) c…

思路: 随机增量法 (好吧这数据范围并不用) //By SiriusRen #include <cmath> #include <cstdio> #include <algorithm> using namespace std; typedef double db; int n; ],ans; P operator-(P a,P b){return P(a.x-b.x,a.y-b.y);} db dis(P a){return sqrt(a.x*a.x+a.y*a.y)…

基本小圆覆盖模板题 #include <iostream> #include <algorithm> #include <cmath> using namespace std; int X,Y; int n; const double eps=0.00000001; struct point{ double x,y; }p[550]; struct Circle{ point cent; double r; }cir; double dist(point x, poin…

传送门 最小圆覆盖模板. //Achen #include<algorithm> #include<iostream> #include<cstring> #include<cstdlib> #include<vector> #include<cstdio> #include<queue> #include<cmath> ; typedef long long LL; typedef double db; us…

//第一期 计算几何题的特点与做题要领: 1.大部分不会很难,少部分题目思路很巧妙 2.做计算几何题目,模板很重要,模板必须高度可靠. 3.要注意代码的组织,因为计算几何的题目很容易上两百行代码,里面大部分是模板.如果代码一片混乱,那么会严重影响做题正确率. 4.注意精度控制. 5.能用整数的地方尽量用整数,要想到扩大数据的方法(扩大一倍,或扩大sqrt2).因为整数不用考虑浮点误差,而且运算比浮点快. 一.点,线,面,形基本关系,点积叉积的理解 POJ 2318 TOYS(推荐) http:/…